I am trying to use split function without empty string. For instance, from a string
['#1(X,Y)', '#2(X,Z)', '#3(Z,Y)']
I want to get:
[ ['#1', 'X', 'Y'],['#2', 'X', 'Z'],['#3', 'Z', 'Y']]
I tried
[ re.split('[(),]', item) for item in string ]
but I get
[ ['#1', 'X', 'Y', ''],['#2', 'X', 'Z', ''],['#3', 'Z', 'Y', '']]
How can I remove ''?
Thanks
It's ugly but you could remove the last element of each sub-list (assuming they are always present and always at the end):
[re.split('[(),]', item)[:-1] for item in string]
You can filter out the empty characters inside the comprehension:
[ [each for each in re.split('[(),]', item) if each != ''] for item in string ]
Out[77]: [['#1', 'X', 'Y'], ['#2', 'X', 'Z'], ['#3', 'Z', 'Y']]
If you are sure empty string is always the last element, you can just discard the last element using the solution provided by @jtlz2
[ re.split('[(),]', item)[:-1] for item in string ]
Out[78]: [['#1', 'X', 'Y'], ['#2', 'X', 'Z'], ['#3', 'Z', 'Y']]
Another option is filter bool:
import re
string = ['#1(X,Y)', '#2(X,Z)', '#3(Z,Y)']
print([list(filter(bool, re.split('[(),]', item))) for item in string])
[['#1', 'X', 'Y'], ['#2', 'X', 'Z'], ['#3', 'Z', 'Y']]
You could strip the ) before splitting.
[re.split('[(,]', s.strip(')')) for s in l]
