Multiple string match in regex Python

Question

I want to find a match in string for the following pattern (field1)(field2)(field3)

field 1 can be either 'alpha' or 'beta' or 'gamma' field 2 is any number(can be whole number or decimal) field 3 is 'dollar' or 'sky' or 'eagle' or 'may'

Input string1 : "There is a string which contains alpha 2 sky as a part of it" Output1: alpha 2 sky

Input string2 : "This sentence contains a pattern beta 10.2 eagle" Output2: beta 10.2 eagle

I'm trying the following code but it's not flexible to include the multiple string matches together. value = " This sentence contains a pattern beta 10.2 eagle"

match = re.findall("beta \d.* dollar", value)

match = re.search("[beta | alpha | gamma]* \d.* [dollar | sky | eagle | may]*", value) something like this ? — Akshay Jain
– Akshay Jain, Commented May 19, 2021 at 3:34

n1colas.m · Accepted Answer · 2021-05-19 11:26:28Z

1

You may use the following regex to collect all the relevant fields

(alpha|beta|gamma) : capture group - alternation with one of this words
\s+ : follow by 1+ whitespaces
( : capture group
- \d+ : 1+ digits, follow by
- (?:\.\d+)? : (an optional) non-capturing group - literal '.' follow by 1+ digits
) : close capture group
\s+ : follow by 1+ whitespaces
(dollar|sky|eagle|may) : capture group - alternation with one of this words

import re
regex = r'(alpha|beta|gamma)\s+(\d+(?:\.\d+)?)\s+(dollar|sky|eagle|may)'

s = '''
There is a string which contains alpha 2 sky as a part of it
This sentence contains a pattern beta 10.2 eagle
'''

match = re.finditer(regex, s)

for m in match:
     print(m.group(0))

# alpha 2 sky
# beta 10.2 eagle

edited May 19, 2021 at 11:26

answered May 19, 2021 at 3:38

n1colas.m

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1 Comment

ssr Over a year ago

Thank you so much. This works ! Would be great if you could explain this, as I'm new to regex.

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