Getting a values from an array based on a sequential order

Question

Suppose I have an array like such:

var test_array = [0.1, 2.1, 0.7, 5.4, 3.2, 1.6];

I basically want to grab the first 2 values in the array, place them into 2 separate variables and then move on to the next step, like so:

var test_array = [0.1, 2.1, 0.7, 5.4, 3.2, 1.6];
test_array.sort();
for (let i=0;i< test_array.length -1; i++) {
   var j = i + 1;
   var pt_one = test_array[i];
   var pt_two = test_array[j];
   console.log("pt_one = " + pt_one);
   console.log("pt_two = " + pt_two);
   
}

Is there a more efficient way to do this? Could the forEach() method be used somehow?

forEach might be a bit better, but not by much. Your current code is fine. — CertainPerformance
– CertainPerformance, Commented May 19, 2021 at 22:45
There's little need for the j variable, just write test_array[i+1] — Barmar
– Barmar, Commented May 19, 2021 at 22:48

ealmonte · Accepted Answer · 2021-05-19 23:04:01Z

1

You could try this using forEach:

test_array.forEach((n, i, arr) => {
  var [pt_one,pt_two] = test_array.slice((arr.length - i) * -1);
})

answered May 19, 2021 at 23:04

ealmonte

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1 Comment

gwydion93 Over a year ago

This is almost perfect except for the last iteration puts pt_one = 100; pt_two = undefined;

StackSlave · Accepted Answer · 2021-05-19 23:04:20Z

1

It may not be much better, but your length is incorrect anyways. I thought you might want to see two increments at a time:

let test_array = [0.1, 2.1, 0.7, 5.4, 3.2, 1.6, 10, 100], pt_one, pt_two;
test_array.sort((a, b)=>a-b);
for(let i=0,n=1,l=test_array.length; i<l; i+=2,n+=2){
  pt_one = test_array[i]; pt_two = test_array[n];
  console.log('pt_one = '+pt_one); console.log('pt_two = '+pt_two);
}

I noticed you will have a problem with that sort, as well.

edited May 19, 2021 at 23:04

answered May 19, 2021 at 22:56

StackSlave

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1 Comment

gwydion93 Over a year ago

More concise, but not quite what I am looking for.

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