Python url joining with parameters

Question

Suppose I had a URL composed of a host,(e.g. stackoverflow.com) a path in that host (e.g. questions/ask) and finally some url arguments (param1=5,param2=st...)

So the final url would have been something like http://HOST/PATH?param1=x&param2=y&param3=zw

Is there a build in function which would construct that url based on the host, path and params dictionary? I wasn't able to find any way to do that which doesn't involve manual string concatenation, and I feel like this probably shouldn't be done manually if that can be avoided. (Perhaps I'm wrong, since unlike file paths, urls are platform independent and pretty consistent)

I tried using urllib.parse and several other methods, but didn't find one that supported such a general url without some manual concatenation.

Maybe urllib.urlunparse() or urllib.urlunsplit()?

gen_Eric
– gen_Eric

2021-05-21 17:51:30 +00:00
Commented May 21, 2021 at 17:51 — gen_Eric
– gen_Eric, Commented May 21, 2021 at 17:51

gen_Eric · Accepted Answer · 2021-05-21 17:58:14Z

1

I think you're looking for urlunsplit(). You need to build a list/tuple matching the result from urlsplit() (5 elements), then urlunsplit() will do what you want.

from urllib.parse import urlunsplit

urlData = ['https', 'stackoverflow.com', 'questions/ask', 'param1=5&param2=st', '']
url = urlunsplit(urlData)

print(url)
# https://stackoverflow.com/questions/ask?param1=5&param2=st

answered May 21, 2021 at 17:58

gen_Eric

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