Python eval integer in string, and return integer instead of ascii char

Question

I'm getting some data from a file, which looks like this:

[200, "Hello", "World"]

Now, since this is a file, this array is inside a string; I turn it into an array using eval(). This works fine BUT the integer at the start is converted to an ascii char, instead of an integer as I want it to (the euro sign).

How can I fix this?

This worked fine for me. >>> z = eval("[200, \"hello\", \"world\"]") >>> z [200, 'hello', 'world'] — Grim
– Grim, Commented Jul 21, 2011 at 8:47
@Judge John Deed ascii char ? Which ascii char ? I don't observe what you describe — eyquem
– eyquem, Commented Jul 21, 2011 at 8:47

Kimvais · Accepted Answer · 2011-07-21 08:47:30Z

2

You could use the simplejson module. E.g.

>>> import simplejson
>>> a = simplejson.loads('[200, "Hello", "World"]')
>>> print a
[200, 'Hello', 'World']

This way "malicious" data such as os.execvp() would not be evaluated but an JSONDecodeErrorwould be thrown.

answered Jul 21, 2011 at 8:47

Kimvais

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John La Rooy · Accepted Answer · 2011-07-21 10:00:22Z

2

You can use literal_eval. Really depends on the source - is the source speaking Python or JSON - there is a lot of overlap where they have identical representations

>>> from ast import literal_eval
>>> literal_eval('[200, "Hello", "World"]')
[200, 'Hello', 'World']

answered Jul 21, 2011 at 10:00

John La Rooy

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