XSLT template to replace string with string Including HTML Tags

Question

I have this template to replace once string with another:

<xsl:template name="X">
<xsl:param name="field"/>
<xsl:param name="target"/>
<xsl:param name="change"/>
<xsl:value-of select='replace($field, $target, $change )' />  
</xsl:template>

This is how I am calling it:

<xsl:call-template name="X">
<xsl:with-param name="field" select="artist"/>
<xsl:with-param name="target" select="'\\n'"/>
<xsl:with-param name="change" select="'&#10;'"/>
</xsl:call-template>

This works in most cases except for the case demonstrated here.
I am trying to replace the string "\n" with a HTML line break   or  .
I want an actual new line not the tag visible in the output. I know that it is matching on the \n but I can not make the line break happen. I either get a literal   in the output or nothing happens.

Mads Hansen · Accepted Answer · 2021-05-28 18:07:53Z

1

You will need to change your approach. Your template is using replace() which works with strings. You want to replace with markup. I'd use xsl:analyze-string instead:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    exclude-result-prefixes="xs"
    version="2.0">
    
    <xsl:output method="xml" encoding="UTF-8" indent="yes"/>
    
    <xsl:template match="/">
      <xsl:variable name="break"><br/></xsl:variable>
            
      <xsl:call-template name="X">
        <xsl:with-param name="field" select="artist"/>
        <xsl:with-param name="target" select="'\n'"/>
        <xsl:with-param name="change" select="$break"/>
      </xsl:call-template>
    </xsl:template>
    
    <xsl:template name="X">
      <xsl:param name="field"/>
      <xsl:param name="target"/>
      <xsl:param name="change"/>
      <!-- <xsl:value-of select='replace($field, $target, $change )' />-->
      <xsl:analyze-string select="$field" regex="{$target}">
        <xsl:matching-substring>
          <xsl:sequence select="$change"/>
        </xsl:matching-substring>
        <xsl:non-matching-substring>
          <xsl:value-of select="."/>
        </xsl:non-matching-substring>
      </xsl:analyze-string>
    </xsl:template> 
    
</xsl:stylesheet>

answered May 28, 2021 at 18:07

Mads Hansen

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4 Comments

Alex Over a year ago

Fantastic! it works for strings and ! Can you tell me what the curly braces do in this case? {$target}

Mads Hansen Over a year ago

the curly braces are an Attribute Value Template w3.org/TR/2021/REC-xslt20-20210330/#attribute-value-templates. The @regex was expecting a literal string, so in order to resolve the value of $target needed the AVT, otherwise it would use $target as the regex.

Alex Over a year ago

I'm also trying to replace an actual new line in the input with   I tried matching on 
 and  but neither seem to match.

Mads Hansen Over a year ago

Post a simplified example of your input XML and XSLT in a qustion.

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