parse json with a callback function in android

Question

I am firing a request through my android application using HttpPost , as the request is returning a JSON Callback function , i don't know how to handle it and parse it.

returned format:

handleEmployeeResponse({
  "records": [
    {
      "fullDesc": "Records for employe",
      "id": "Emp_1",
      "name": "Jack"
    }
  ]
});

in a firebug i can see as a response text

handleEmployeeResponse({"records":[{"fullDesc":"Records for employe","id":"Emp_1","name":"Jack"}]});

if i will parse the above response using JSONObject jObject = new JSONObject(jString); i am surely gonna get JSON parsing error as the above response is not valid json at all so i have to remove "handleEmployeeResponse , ( , ); " form the response string then i need to pass it so JSONObject can anyone tell me how to parse json with a callback function in android

Is handleEmployeeResponse a Java function or is the code you posted all received text? — Zoran Zaric
– Zoran Zaric, Commented Jul 21, 2011 at 12:32
@Hunt by returning a JSON Callback function, do you mean a JSON string i.e. the one you posted ? or a POJO ? — olamotte
– olamotte, Commented Jul 21, 2011 at 12:34
@olamotte handleEmployeeResponse({"records":[{"fullDesc":"Records for employe","id":"Emp_1","name":"Jack"}]}); this is how it returns from the server — Hunt
– Hunt, Commented Jul 21, 2011 at 12:37

Mark Fisher · Accepted Answer · 2011-07-21 14:20:25Z

0

It looks like your service is returning a response in the JSONP format (JSON with Padding). You either need to regex out the JSON message, or find out a way to ask the service not to return the padding.

answered Jul 21, 2011 at 14:20

Mark Fisher

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olamotte · Accepted Answer · 2011-07-21 12:47:57Z

0

Have a look here : you should use the JSONTokener Class and thus get a JSONObject corresponding to your structure.

TOKENER

the example is pretty self-explanatory.

answered Jul 21, 2011 at 12:47

olamotte

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2 Comments

Hunt Over a year ago

i am getting java.lang.ClassCastException: java.lang.String at JSONObject object = (JSONObject) new JSONTokener(responseString).nextValue()

olamotte Over a year ago

@Hunt did you try with another JSON string ? Obviously the returned string as an overhead, and the valid JSON starts here : you should then truncate the string to : { "records": [ { "fullDesc": "Records for employe", "id": "Emp_1", "name": "Jack" } ] } if you have any doubt use JSONLint

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