How to return an array which is not equal to a specific number in ReactJS?

Question

Number = 10;

occupiedBeds = [2, 8];

I want to return numbers from 1 to number not equal to occupiedBeds, that is:

[1, 3, 4, 5, 6, 7, 9, 10]

My code so far:

 const vacantBeds = (number) => {
      const occupiedBeds = patientsData && patientsData.map((patient) => Number(patient.room.slice(-1)[0].bed))
    
      let numArr = [...Array(number).keys()].map((x) => x + 1)
    
      let filtered = numArr.filter((x) => x !== occupiedBeds)
    
      return filtered.map((bed) => (
        <option key={bed} value={bed}>
          {bed}
        </option>
      ))
    }

But x is a number e.g. 3 and occupiedBeds is array [2, 8] How do I compare these two which are not same type. — Ahmed Ibrahim
– Ahmed Ibrahim, Commented May 30, 2021 at 15:27
ah, sorry, misread the question. So, given number=10 and beds=[2,8], you want to return [1, 3,4,5,6,7, 9,10] - is that correct? — georg
– georg, Commented May 30, 2021 at 15:29
Then just use numArr.filter((x) => !occupiedBeds.includes(x)) — Ravikumar
– Ravikumar, Commented May 30, 2021 at 15:32
Yes. Thank you this one solved my problem. Thanks million times — Ahmed Ibrahim
– Ahmed Ibrahim, Commented May 30, 2021 at 15:35

Udit · Accepted Answer · 2021-05-30 15:34:01Z

2

This should work for you

  let filtered = numArr.filter( x => !occupiedBeds.includes(x))

answered May 30, 2021 at 15:34

Udit

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