How to call a function from another function without constructor in React native?

Question

I need to call from my function "RegisterTaster" to my function "endRegisterAlert" but actually im not using constructor because i use the class like a const in react native.

How can i call the function ?

const Validator=(props)=>{

  async function RegisterTaster(){
    //do something...
    endRegisterAlert();
  }

  function endRegisterAlert(){
   //do something
  }

 return(
    <Button onPress={async ()=> await RegisterTaster() }> 
                    <Text >Register</Text> 
    </Button
  );
 }

export default Validator;

Zhang TianYu · Accepted Answer · 2021-05-30 23:41:04Z

1

Just do this.

const Validator=(props)=>{

  async function RegisterTaster(){
    //do something...
    endRegisterAlert();
  }

  function endRegisterAlert(){
   //do something
  }

 return(
    <Button onPress={RegisterTaster}> 
                    <Text >Register</Text> 
    </Button
  );
 }

answered May 30, 2021 at 23:41

Zhang TianYu

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Comments

Kescript · Accepted Answer · 2021-05-30 23:42:17Z

0

You are using a function-based React Component.

Everything is right except for the part that you are awaiting an async function.

Do it this way:

return(
  <Button onPress={RegisterTaster}> 
     <Text>Register</Text> 
  </Button
);

OR:

return(
  <Button onPress={() => RegisterTaster()}> 
     <Text>Register</Text> 
  </Button
);

Either way, it should work.

answered May 30, 2021 at 23:42

Kescript

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