How create an object with keys which come from an array of keys without loops?

Question

There is an array which its items should be the keys of an object. As an example:

['key1', 'key2', 'key3']

is my array. I need to have it like this object:

{
  'key1': '',
  'key2': '',
  'key3': ''
}

As it might be so items in array prefer not to use loops. How can create object without loops?

By "without loops", do you mean "without for loops" or "without any kind of looping through an array"? — georg
– georg, Commented Jun 2, 2021 at 15:12
Any kind of loops. Not for , while, ... . It takes time to do it. — Atousa Darabi
– Atousa Darabi, Commented Jun 2, 2021 at 15:13
That's not possible. There's no built-in function in javascript like python's dict.fromkeys. Your best bet would be Object.fromEntries(keys.map(k => [k, ''])), but that's a loop too. — georg
– georg, Commented Jun 2, 2021 at 15:16
obj = { [arr[0]]: "", [arr[1]]: "", [arr[2]]: "", }; That's it. — ikhvjs
– ikhvjs, Commented Jun 2, 2021 at 15:18
Does this answer your question? Create an object from an array of keys and an array of values — outis
– outis, Commented Sep 1, 2022 at 7:57

Carsten Massmann · Accepted Answer · 2021-06-02 15:26:27Z

0

This is also a loop, but at least it is a one-liner:

const res=['key1', 'key2', 'key3'].reduce((a,c)=>(a[c]='',a),{});

console.log(res)

answered Jun 2, 2021 at 15:26

Carsten Massmann

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1 Comment

Atousa Darabi Over a year ago

However it is a loop though, but worked better than others.

Kyle · Accepted Answer · 2021-06-02 15:54:08Z

-1

I don't know why you're against using a loop. If you require the object to be created dynamically you won't really get away with not using a loop of some kind.

This solution technically doesn't directly use a loop ... but it's a silly solution and I don't recommend it.

const keys = ['key1', 'key2', 'key3'];
const res = Object.fromEntries(
  JSON.parse(
    JSON.stringify(keys).replace(/"([^"]+)"/g,'["$1",""]')
  )
);
console.log(res);

answered Jun 2, 2021 at 15:54

Kyle

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2 Comments

ikhvjs Over a year ago

isn't the replace method loop through the string as well?

Kyle Over a year ago

@ikhvjs depends on your definition of a loop. Internally, yeah, there’s a loop. But in the code itself there is no actual loop.

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