Here is my basic code:
import numpy as np
a = numpy.asarray([ [1,2,3], [4,5,6], [7,8,9] ])
I want to print the arrays as follows:
1 4 7
2 5 8
3 6 9
Also, how would I approach the same concept if my a array has 1000 embedded list in it?
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Have you tried writing one or two loops?mkrieger1– mkrieger12021-06-02 20:50:25 +00:00Commented Jun 2, 2021 at 20:50
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@mkrieger1 Trying to think how to do two loops. Any hints?user8607309– user86073092021-06-02 20:53:02 +00:00Commented Jun 2, 2021 at 20:53
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For each column: print each column separated by line breaks; For each row in every column: print each value separated by spacesmkrieger1– mkrieger12021-06-02 20:56:29 +00:00Commented Jun 2, 2021 at 20:56
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2 Answers
Here is a powerful one-line solution without loops:
print('\n'.join(map(lambda line: ' '.join(map(str, line)), a.T)))
a.T transpose the 2D array, the first map encode a line in a string and the second one concatenate the string lines (by using \n between).
This is an alternative version with generators (likely slower):
print('\n'.join(' '.join(str(item) for item in line) for line in a.T))
Yet another solution with one loop (likely even slower):
for line in a.T:
print(' '.join(str(item) for item in line))
Note the last version produce a trailing new line.
2 Comments
user8607309
Richard can you show how to do it in a loop as well please?
Jérôme Richard
@user8607309 I edited the question to include that.
You could also make use of str:
print(str(a.T).translate(str.maketrans({'[':'',']':''})))
1 4 7
2 5 8
3 6 9
print(str(a.T).replace('[', '').replace(']',''))
1 4 7
2 5 8
3 6 9
print(str(a.T).translate(str.maketrans({'[':'',']':''})).replace('\n ', '\n'))
1 4 7
2 5 8
3 6 9
