I'm making a little data base on python.
my_list = ['jack', 'liam', 'gary', 'poly']
I want to convert the list into this
result = [('jack', 'liam'),('liam', 'gary'),('gary', 'poly')]
Is there anyway i can do this?
-
1See this post stackoverflow.com/questions/11487049/python-list-of-lists, seems quite relevant.user15479632– user154796322021-06-03 10:27:04 +00:00Commented Jun 3, 2021 at 10:27
-
Or perhaps this post could help too? stackoverflow.com/questions/6614891/…Party-with-Programming– Party-with-Programming2021-06-03 10:28:09 +00:00Commented Jun 3, 2021 at 10:28
Add a comment
|
5 Answers
Use list comprehension
- Iterate till second last value of the list
- get current and next value as a tuple.
my_list = ['jack', 'liam', 'gary', 'poly']
new_list = [(my_list[i],my_list[i+1]) for i in range(len(my_list)-1)]
print(new_list)
>> [('jack', 'liam'), ('liam', 'gary'), ('gary', 'poly')]
Or Use zip()
which will return consecutive combinations as tuple.
my_list = ['jack', 'liam', 'gary', 'poly']
new_list = list(zip(my_list, my_list[1:]))
print(new_list)
>> [('jack', 'liam'), ('liam', 'gary'), ('gary', 'poly')]
Comments
zip will return a tuple from two iterables; if you take the same list, but shifted as you wish (in this case, one element forward) you can have your expected result.
Also, the generator will exhaust on the shortest iterable (the second one).
>>> [(a,b) for (a,b) in zip(my_list, my_list[1:])]
[('jack', 'liam'), ('liam', 'gary'), ('gary', 'poly')]
3 Comments
assda
can you explain zip here, so i can add a comment to my code to remember.
Hamza usman ghani
list(zip(my_list, my_list[1:])) will work the same.my_list = ['jack', 'liam', 'gary', 'poly']
result_list = [(my_list[i],my_list[i+1]) for i in range(len(my_list) - 1)]
print(result_list)
Output
[('jack', 'liam'), ('liam', 'gary'), ('gary', 'poly')]
We can fetch 2 elements into a tuple till we iterate and reach the second last element.
Comments
result = []
my_list = ['jack', 'liam', 'gary', 'poly']
for i, item in enumerate(my_list):
if i+1 == len(my_list): break
result.append((item, my_list[i+1]))
Or more Pythonic and elegant way:
result = [(item, my_list[i+1]) for i, item in enumerate(my_list) if i+1 < len(my_list)]
Comments
my_list = ['jack', 'liam', 'gary', 'poly']
result = []
for i in range(0, len(my_list)):
if not i > len(my_list)-2:
result.append((my_list[i], my_list[i+1]))
output
[('jack', 'liam'), ('liam', 'gary'), ('gary', 'poly')]
