Bash completion in function?

Question

I currently have the following Bash function:

function xcd {
        if [ "$#" -gt 1 ]; then
                echo "Usage: xcd [<path>]" >&2
                return 1
        fi

        cd "/some/commonly/used/path/${1}"
}

I'd like for this to support Bash completion - when I type xcd foo, I'd like it to complete as though I'd typed cd /some/commonly/used/path/foo. Is there any way to get Bash to be smart about this - presumably by observing how ${1} is used - without just writing a Bash completion by hand?

Cyrus · Accepted Answer · 2021-06-03 19:00:06Z

1

Replace your function in your ~/.bashrc with this:

CDPATH="/some/commonly/used/path"

I assume that CDPATH is not used so far. Source your ~/.bashrc and then you can use cd foo with bash's completion.

answered Jun 3, 2021 at 19:00

Cyrus

90.2k15 gold badges112 silver badges173 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Bash completion in function?

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related