Serialize json 2-dimensional array, send two arrays, or other?

Question

I have to send a 2-dimensional array (along with several other variables) to PHP using jQuery.ajax(). I believe my options are:

Serialize to json with JSON-js
Send both arrays as csv strings and recompile on the other side.

My questions are:

A. Is there anything wrong with option #2 if I'd prefer not to include another library for a small function? B. Are there other options besides options #1 and #2?

Thanks!

Since you've included jQuery as a tag, could you just use the jQuery .serializeArray function to serialize the JavaScript array and PHP's json_decode to decode it? — Francois Deschenes
– Francois Deschenes, Commented Jul 21, 2011 at 22:54
.serializeArray ...the name would suggest it's exactly what I'm looking for. I looked at the link you provided and it seems that it takes $(":input") or $('form') and returns an array with the name and values of the form elements. So (if I were using a form) it leaves me with the same problem I had before, unfortunately. But thanks for the link - good to know it exists! — Kyle Cureau
– Kyle Cureau, Commented Jul 21, 2011 at 23:06

ChristopheCVB · Accepted Answer · 2011-07-21 22:54:25Z

2

You can try :

JSON.stringify(array);

No extra library required.

answered Jul 21, 2011 at 22:54

ChristopheCVB

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2 Comments

Kyle Cureau Over a year ago

JSON.stringify is missing from jQuery 1.4.1, which is the lib I'm using. Not sure if it was reintroduced in newer versions. JSON.parseJSON allows for the decoding, but no functions for the encoding that I'm aware of. Take a look at this: stackoverflow.com/questions/2277405/…

Kyle Cureau Over a year ago

Cool...I tried to find support. IE7 and below no support. Any other one you know of?

Jonathan M · Accepted Answer · 2011-07-21 22:54:41Z

0

I'm sure there are other options; there's always a million ways to skin a cat. But I'd suggest option #1. When you send it as a JSON string (using a library that is quite small and only has two methods), you can then decode it in PHP using json_decode. No fuss, no muss.

answered Jul 21, 2011 at 22:54

Jonathan M

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Comments

ngn · Accepted Answer · 2011-07-21 22:57:28Z

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A. Is there anything wrong with option #2 if I'd prefer not to include another library for a small function?

You might have issues with escaping/unescaping some characters.

B. Are there other options besides options #1 and #2?

Surely there must be. But I'd go with JSON, it's the simplest and cleanest solution.

answered Jul 21, 2011 at 22:57

ngn

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