JS return 1st element of 2d array sorted

Question

I have following 2D array: [["fox", "100"], ["the", "1"], ["quick", "50"]]

And want to store only the first element of the array, but sorted based on the second value.

Desired output: the,quick,fox

I have written a loop that iterates over the first elements which seems to work, however I cannot get it sorted based on the second value:

for (var i = 0; i < inputArr.length; i++) {
  x1 += inputArr[i][0];
  if(i != inputArr.length - 1){ 
   x1 = x1 + ",";
  }
 }

  
Write(x1); //outputs -> fox,the,quick

My naive attempt would be inputArr.sort((a,b) => a[1]-b[1]).map(([a]) => a).flat().join(',') - flat might be unneeded though... — evolutionxbox
– evolutionxbox, Commented Jun 8, 2021 at 9:32

Best Partner · Accepted Answer · 2021-06-08 09:37:08Z

2

You can use sort function of Array. The sort function takes a lambda function with 2 inputs based on return value decides the order

let arr = [["fox", "100"], ["the", "1"], ["quick", "50"]];

let output= arr.sort((a,b) => a[1]-b[1]).map(e => e[0]).join(",");

edited Jun 8, 2021 at 9:37

Best Partner

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answered Jun 8, 2021 at 9:31

Rajdeep D

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2 Comments

ikhvjs Over a year ago

Whenever I saw "5" - "1" , it always shocks me. I always use Number() or + before doing maths with js number. please note: "5" + "1" = "51" but "5"-"1" = 4.

Yoshi Over a year ago

Note that sort manipulates the source array. Meaning arr will be sorted as well. This might or might not be desirable. If not, slice or concat are simple ways to make a copy before sorting.

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