How to convert specific CURL request to Python

Question

I have the following Curl request:

curl -v --location --request POST 'http://127.0.0.1:8080/abc' \--header 'Content-Type: application/json' \--data-raw '{data}'

I tried using pycurl and requests command. Also tried to put headers but it was of no use.

My tried code:

requests = "curl -v --location"

a = "http://127.0.0.1:8080/abc"

headers = {'Content-Type': 'application/json'}

r = requests.post(url=a, headers= headers , params=data)

Animeta · Accepted Answer · 2021-06-10 06:00:30Z

2

Is this works? https://curl.trillworks.com/

import requests

headers = {
    'Content-Type': 'application/json',
}

data = '{data}'

response = requests.post('http://127.0.0.1:8080/abc',
                         headers=headers,
                         data=data)

answered Jun 10, 2021 at 6:00

Animeta

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1 Comment

Animeta Over a year ago

@Ashwinikumarjha If this worded fine, please mark my answer as accepted. Thank you.

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