Check if an object in an array is exist in another array, then change the value of that another array in Javascript

Question

i have an array A

const arrayA = [
          {
            id:a,
            check:false
          },
          {
            id:b,
            check:false
          },
          {
            id:c,
            check:false
          }

and an array B

const arrayB = [
  {
    id:a,
  },
  {
    id:b,  
  }
]

and i want to check if arrayB is exist arrayA by id, then change check to true. Using lodash or js array methods

Dharman · Accepted Answer · 2021-06-11 14:11:31Z

4

Hopefully I understood your question correctly but this is the solution I came up with.

arrayA.map((item) => ({ ...item, check: arrayB.some(({ id: idB }) => item.id === idB ) }))

edited Jun 11, 2021 at 14:11

Dharman♦

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answered Jun 11, 2021 at 14:06

ChrisMcCool

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Comments

TechySharnav · Accepted Answer · 2021-06-11 13:59:45Z

2

You can use nested forEach loops, and check, if id matches then set check to true.

const arrayA = [{
    id: "a",
    check: false
  },
  {
    id: "b",
    check: false
  },
  {
    id: "c",
    check: false
  }
]

const arrayB = [{
    id: "a",
  },
  {
    id: "b",
  }
]

arrayB.forEach((b)=>{
  arrayA.forEach((a)=>{
   if(b.id == a.id){
    a.check = true;
   }
  })
})

console.log(arrayA);

answered Jun 11, 2021 at 13:59

TechySharnav

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Comments

L. Monty · Accepted Answer · 2021-06-11 14:03:29Z

0

You could create an array containing the ids of arrayB and then check the objects in arrayA like

const arrayA = [
          {
            id: 'a',
            check:false
          },
          {
            id:'b',
            check:false
          },
          {
            id:'c',
            check:false
          } ];
          
const arrayB = [
  {
    id:'a',
  },
  {
    id:'b',  
  }
];

const idsB = arrayB.map( obj => obj.id);
arrayA.forEach(obj => { if(idsB.indexOf(obj.id) > -1) obj.checked = true; } );
arrayA.forEach(obj => {console.log(JSON.stringify(obj))});

answered Jun 11, 2021 at 14:03

L. Monty

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Comments

demee · Accepted Answer · 2021-06-11 14:11:01Z

0

I could come up with this, which is not different than double loop, but may read easier.

arrayA.map((a) => {
    a.check = arrayB.findIndex((b) => b.id === a.id) != -1;
    return a;
});

answered Jun 11, 2021 at 14:11

demee

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Comments

Sparrow · Accepted Answer · 2021-06-11 14:18:07Z

0

Try this code it may help you

const arrayA = [
  {id:'a',check:false},
  {id:'b',check:false},
  {id:'c',check:false}
]
const arrayB = [
  {id:'a',},
  {id:'b',}
]

arrayB.map(i => {
   return i.check = arrayA.find(item => i.id == item.id)?.check;
});

console.log(arrayB)

answered Jun 11, 2021 at 14:18

Sparrow

3902 silver badges13 bronze badges

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