PHP, Fatal error: Call to undefined method calling function from another class

Question

I have a simple PHP structure.

In admin_keys.php i have:

<?php
class admin_keys
{
    public $key;
    private $arr_keys = array("1", "2", "3");
    public function check_key_admin()
    {
        if(in_array($this->key,$this->$arr_keys))
        {
            return true;
        }else
        {
            return false;
        }
    }
}
?>

In ok.php i have:

<?php
include_once '../../all_keys.php';
$admin_keys = new admin_keys();
$admin_keys->key = "vailozluon";
$_isAdmin = $admin_keys->check_key();
  if( _isAdmin== false)
  {
    echo 'deo phai';
  }else { echo 'ok';}
?>

Im new so just bear with me I don't know why this is return Uncaught Error: Call to undefined method admin_keys::check_key any help will be appreciated.

thanks!

check_key_admin != check_key.

tkausl
– tkausl

2021-06-14 05:26:23 +00:00
Commented Jun 14, 2021 at 5:26 — tkausl
– tkausl, Commented Jun 14, 2021 at 5:26

vins · Accepted Answer · 2021-06-14 06:36:50Z

1

you are refering to function (i.e. check_key()) that does not exists in your class admin_keys. You have function named check_admin_key() but you are trying to access it as check_key() which does not exist apparently throwing an error. So just change the name of the function being called as

$_isAdmin = $admin_keys->check_admin_key();

answered Jun 14, 2021 at 6:36

vins

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