Unexpected EOF while parsing Syntax Error in Python

Question

I just started using Python's keyboard module. I was exploring with the code below until there was a error occurring at the end on line 5. The goal of the code below is to detect if I pressed the "a" on my keyboard. I attempted to put a semicolon at the end of the print function, and I tried to replace the print("A") with pass and break but Python gave me the same error as before.

import keyboard
while True:
    try:
        if keyboard.is_pressed('a'):
            print("A")

Output:

File "c:\users\emma\mu_code\keyboard.py", line 6

Syntax Error: unexpected EOF while parsing

Why do I have this syntax error and how can I get rid of it?

Kyle · Accepted Answer · 2021-06-15 03:31:43Z

3

In your code add the except block, like so:

import keyboard
while True:
    try:
        if keyboard.is_pressed('a'):
            print("A")
   except:
      #do something else, if there is an error, or any other key is pressed

If u dont know if u need try except, then just dont keep it in the try block:

import keyboard
while True:
    if keyboard.is_pressed('a'):
            print("A")

answered Jun 15, 2021 at 3:31

Kyle

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7 Comments

Kyle Over a year ago

See also: w3schools.com/python/python_try_except.asp

EmmaGao8 Over a year ago

I tried that replit.com/@EmmaGao8/Keyboard-Sensor#main.py but nothing happens if I press the q key.

Kyle Over a year ago

Ok i will try it on replit later, but try to install python in ur pc, and then see if it works

EmmaGao8 Over a year ago

I already installed Python, but if I try there, they say that keyboard isn't defined, so I just use replit.com

Kyle Over a year ago

pip install keyboard in command prompt as keyboard doesnt come pre installed, it happened to me too

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Md Atifuzzaman · Accepted Answer · 2021-06-15 03:51:42Z

2

You didn't add except part. If you are using try/except statement you need an except statement.

Make it.

import keyboard
while True:
    try:
        if keyboard.is_pressed('a'):
            print("A")
    else:
       # Rest code . If you don't want to do anything then simply pass
       pass

answered Jun 15, 2021 at 3:51

Md Atifuzzaman

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