$string = "|1|2|3|4|";
$array = explode("|", $string, -1);
foreach ($array as $part) {
echo $part."-";
}
I use -1 in explode to skip the last "|" in string. But how do I do if I also want to skip the first "|"?
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4 Answers
You can use trim to Strip | from the beginning and end of a string and then can use the explode.
$string = "|1|2|3|4|";
$array = explode("|", trim($string,'|'));
Comments
preg_split(), and its PREG_SPLIT_NO_EMPTY option, should do just the trick, here.
And great advantage : it'll skip empty parts even in the middle of the string -- and not just at the beginning or end of it.
The following portion of code :
$string = "|1|2|3|4|";
$parts = preg_split('/\|/', $string, -1, PREG_SPLIT_NO_EMPTY);
var_dump($parts);
Will give you this resulting array :
array
0 => string '1' (length=1)
1 => string '2' (length=1)
2 => string '3' (length=1)
3 => string '4' (length=1)
Comments
take a substring first, then explode. http://codepad.org/4CLZqkle
<?php
$string = "|1|2|3|4|";
$string = substr($string,1,-1);
$array = explode("|", $string);
foreach ($array as $part) {
echo $part."-";
}
echo PHP_EOL ;
/* or use implode to join */
echo implode("-",$array);
?>
Comments
You could use array_shift() to remove the first element from the array.
