count array unique on mixed array [duplicate]

Question

I have a mixed array type something like:

Array
(
    [0] => 368
    [1] => Array
        (
            [0] => 384
            [1] => 383
        )

)

I was trying to get the unique count as count(array_unique($arr_val)) but its throwing error: Array to string conversion

I want to count that nested as one type. For example, if another same array [384,383] appear on another index that should not be added on the total count as that won't be the unique one. In this case the unique count should be greater than 1.

The question is not clear. Please, make it easier to understand! — Md Jahid Khan Limon
– Md Jahid Khan Limon, Commented Jun 16, 2021 at 5:36

Biswajit Biswas · Accepted Answer · 2021-06-16 05:55:25Z

0

Use SORT_REGULAR as the second parameter.

$array = ['test', 'test', [10,20,30], [10, 20, 30], [20, 30], 'test_one', 'test_two'];

print_r(array_unique($array, SORT_REGULAR));

Result:

array:5 [
  0 => "test"
  2 => array:3 [
    0 => 10
    1 => 20
    2 => 30
  ]
  4 => array:2 [
    0 => 20
    1 => 30
  ]
  5 => "test_one"
  6 => "test_two"
]

answered Jun 16, 2021 at 5:55

Biswajit Biswas

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Comments

Mindau · Accepted Answer · 2021-06-16 05:55:25Z

0

Primitive algorithm to count unique top level array elements:

hash array top level elements
build temp unique hashes array
count temp array

For example:

$arr = [368, [0 => 384, 1 => 383],[0 => 384, 1 => 383]];

$hashedUniqueArr = [];
foreach ($arr as $val) {
    $hash =  md5(serialize($val));
    if (!in_array($hash, $hashedUniqueArr)) {
        $hashedUniqueArr[] = $hash;
    }
}
echo 'unique top level elements: ' . count($hashedUniqueArr);

answered Jun 16, 2021 at 5:55

Mindau

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