How come inside a function which is inside a class, I can't do this statement:
global $connected = true;
But I can do this:
global $connected;
$connected = true;
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I suggest $GLOBALS associative array with the name of the global variable being the key and the contents of that variable being the value of the array element.Nickool– Nickool2011-07-24 18:49:26 +00:00Commented Jul 24, 2011 at 18:49
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2to clarify there is no problem, I'm just wondering why I can't do it in one statement.David– David2011-07-24 18:51:06 +00:00Commented Jul 24, 2011 at 18:51
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2 Answers
The bringing of $connected into scope, and the assignment of a value to it, are two separate things.
There is no reason for them to be possible in one statement, which wouldn't really make much sense.
Does the following code:
function foo() {
global $x = 5;
}
- Bring the "global expression"
$x = 5into scope? - Bring the "global expression"
5into scope? - Assign
5to the global$x? - Assign
5to the global$xand then bring$xinto scope?
I know of course that you intend for it to mean the latter, and that the first two have no meaning. But, that is not clear from the proposed statement. It would be poor syntax.
answered Jul 24, 2011 at 18:58
Lightness Races in Orbit
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Because inside a function you first have to announce a global variable. It is something you must do in the beginning of the function. That way you can activate a certain variable which was not passed through.
2 Comments
Lightness Races in Orbit
Whilst true, this merely states the facts as the OP already knows. It does not attempt to explain why these facts are so.
Lightness Races in Orbit
Simply put, "because" is not an answer.