Python: threading delay

Question

Using the following to set a 30 second break every 60 seconds, however I do not want the break to start as soon as the script is first run. How can I add an initial delay to the first break?

def Breaktime():
  threading.Timer(60, Breaktime).start()
  print("Breaking for 30 seconds")
  time.sleep(30)

Breaktime()

What do you mean by "30 second break"? What you have there starts a new thread and puts that thread to sleep, uselessly. It isn't going to affect the rest of your program. Is that what you were after? If you want the main code to pause, then you have to put the sleep in the main code. — Tim Roberts
– Tim Roberts, Commented Aug 23, 2021 at 18:19

sberry · Accepted Answer · 2021-06-22 21:14:58Z

1

How about passing an argument? Here is one way to do it.

def Breaktime(break_time=0):
  threading.Timer(60, Breaktime, kwargs={"break_time": 30}).start()
  print("Breaking for 30 seconds")
  time.sleep(break_time)

Breaktime()

answered Jun 22, 2021 at 21:14

sberry

133k20 gold badges145 silver badges171 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

MattC Over a year ago

The rest of the script continues to run when I do this, it prints that it's breaking but doesn't actually stop.

Collectives™ on Stack Overflow

Python: threading delay

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related