Create an object from a python function returns a class

Question

I have a function which returns a class:

def my_function():
    # some logic
    class AClass:
         def __init__(self, argument):
             init()
    return AClass

And when I call this function, it returns a class, not an object of that class, right?

Value = my_function()

My question is how can I create an object from that class AClass?

Thank you.

instance = my_function()(argument)

Paul M.
– Paul M.

2021-06-25 16:55:03 +00:00
Commented Jun 25, 2021 at 16:55 — Paul M.
– Paul M., Commented Jun 25, 2021 at 16:55

tomtomfox · Accepted Answer · 2021-06-25 16:57:11Z

3

my_class = my_function()
my_obj = my_class(arg)

answered Jun 25, 2021 at 16:57

tomtomfox

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Comments

joshmeranda · Accepted Answer · 2021-06-25 17:06:08Z

Since the method returns a reference to a type you can simply use whatever constructor that is defined for the class directly on the return value.

Take this class for example:

class A:
    def __init_(self, n = 0):
        self.__n = n

Lets see what happens when reference the type directly when running the interpreter interactively:

>>> A
<class `__main__.A`>

Now lets return the type in a method:

>>> def f():
>>>    return A
>>> f()
<class `__main__.A`>

Since the value of referencing the class directly and when returned from a method is the same, you can use that returned value the same you would normally. Therefore a = A() is the same as a = f()(). Even if the class takes parameter you can still reference it directly: a = f()(n = 10)

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