I made this to test it for another script.
I have this code that checks if a specific value in users.txt I added it (let's say 21) exists the check function value 21 if it's, then it prints the existing value
But no result with it, where is the problem?
listNum = list(range(1, 101))
def check(z):
with open('users.txt') as f:
for i in range(len(listNum)):
if str(i) in f.read():
result = print(str(listNum[i]))
return result
check(21)
The problem is, that you consume the text file each time you perform f.read(). So in your loop you are not checking if all your numbers are in the file, but only if the very first is in your file, because for the seconds and all following numbers your f.read will result in an empty string, because the end-of-file was already reached.
Try storing the file content instead, like this:
def check(z):
with open('users.txt') as f:
file_content= f.read()
for i in range(len(listNum)):
if str(i) in file_content:
result = str(listNum[i])
print(result)
return result
check(21)
Btw. you don't need to use range objects to iterate over lists. It's more pythonic to do it like this:
def check(z):
with open('users.txt') as f:
file_content= f.read()
for num in listNum:
if str(num) in file_content:
result = print(num)
return str(num)
32 in users.txt it takes only 3 value. How can I fix that
print()returnsNone, soresultisNonein any case.21, The output must be the value that is in the example file