fill an array of pointers to functions in another function in C

Question

I tried to fill my array of pointer to functions in another function but I don't know how I can do it.

Below my function to fill the array

void* fill_tab_f(void (***tab_f))
{

    *tab_f[0] = ft_pt_char;
    *tab_f[1] = ft_pt_str;
    *tab_f[2] = ft_pt_ptr;
    *tab_f[3] = ft_pt_int;
    *tab_f[4] = ft_pt_int;
    *tab_f[5] = ft_pt_un_int;
    *tab_f[6] = ft_pt_hexa_min;
    *tab_f[7] = ft_pt_hexa_maj;
    
    return NULL;
}

Below the declaration of the array of pointers to functions and the call of the function to fill my array.

void(*tab_f[8])(va_list *, Variable*);
fill_tab_f(&tab_f);

Thanks for your answers.

Why can't you do it? Does it fail to compile? Is there an error message? Does it just crash when you try to use it? — Bill Lynch
– Bill Lynch, Commented Jul 9, 2021 at 14:43
Having a triple-asterisk in the parameter, but then dereferencing your array members, seems a bit odd. Why not just assign the function pointers directly? — Robert Harvey
– Robert Harvey, Commented Jul 9, 2021 at 14:45
Instinctively, it feels to me like you should be using array initialization here, not a runtime function. This can all be done at compile time, unless your intent is to change out these functions at will during runtime. See here for more details. — Robert Harvey
– Robert Harvey, Commented Jul 9, 2021 at 14:50

0___________ · Accepted Answer · 2021-07-09 17:15:02Z

2

You are overcomplicating it

typedef int variable ;

void fill_tab_f(void (*tab_f[])(va_list *, variable *))
{

    tab_f[0] = ft_pt_char;
    tab_f[1] = ft_pt_str;
    tab_f[2] = ft_pt_ptr;
    tab_f[3] = ft_pt_int;
    tab_f[4] = ft_pt_int;
    tab_f[5] = ft_pt_un_int;
    tab_f[6] = ft_pt_hexa_min;
    tab_f[7] = ft_pt_hexa_maj;
}

or if function pointer syntax is a bit weird for you:

typedef int variable ;

typedef void (*funcptr)(va_list *, variable *);

void fill_tab_f(funcptr *tab_f)
{

    tab_f[0] = ft_pt_char;
    tab_f[1] = ft_pt_str;
    tab_f[2] = ft_pt_ptr;
    tab_f[3] = ft_pt_int;
    tab_f[4] = ft_pt_int;
    tab_f[5] = ft_pt_un_int;
    tab_f[6] = ft_pt_hexa_min;
    tab_f[7] = ft_pt_hexa_maj;
}

edited Jul 9, 2021 at 17:15

answered Jul 9, 2021 at 15:04

0___________

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2 Comments

0___________ Over a year ago

@EricPostpischil does it matter considering the question?

0___________ Over a year ago

@ChrisDodd well spotted. Too long week at work

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