Multiple OR conditions for words in JavaScript regular expression

Question

I trying to have a regular expression which is finding between two words but those words are not certain one.

2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞASınıfıE10/ENo303

This is my text. I'm trying to find the word between Soyadı and Sınıfı, in this case ERTANĞA, but the word Sınıfı also can be no, numara or any number. This is what I did.

soyad[ıi](.*)S[ıi]n[ıi]f[ıi]|no|numara|[0-9]

[ıi] is for Turkish character issue, don't mind that.

Rukshán Dikovita · Accepted Answer · 2021-07-16 12:04:32Z

2

You can use something like below :

/.*Soyad(ı|i)|S(ı|i)n(ı|i)f(ı|i).*|no.*|numera.*|[0-9]/gmi

Here is the link I worked on : https://regex101.com/r/QXLjLF/1

In JS code:

const regex = /.*Soyad(ı|i)|S(ı|i)n(ı|i)f(ı|i).*|no.*|numera.*|[0-9]/gmi;

var str = `2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞASınıfıE10/ENo303`;


var newStr = str.replace(regex, '');
console.log(newStr);

edited Jul 16, 2021 at 12:04

answered Jul 16, 2021 at 11:21

Rukshán Dikovita

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2 Comments

Kaepxer Over a year ago

Sorry but I have to include insensitive flag also. Why is it returning me all text when I use it with your regex?

Rukshán Dikovita Over a year ago

@Kaepxer sorry, my bad. didn't see the case insensitive requirement before. Please check now. How does string appear when its numbers after ERTANĞA ? if all are numbers after that above will work, else we need to do little adjustment to remove all numbers after Soyadı

The fourth bird · Accepted Answer · 2021-07-16 14:07:52Z

You can use a single capture group to get the word ERTANĞA, keep the character class [ıi] instead of using an alternation for (ı|i) and group the alternatives at the end of the pattern using a non capture group (?:

soyad[ıi](.+?)(?:S[ıi]n[ıi]f[ıi]|n(?:o|umara)|[0-9])

soyad[ıi] Match soyadı or soyadi
(.+?) Capture group 1, match 1 or more chars as least as possible
(?: Non capture group
- S[ıi]n[ıi]f[ıi] Match S and then ı or i etc..
- | Or
- n(?:o|umara) Match either no or numara
- | Or
- [0-9] Match a digit 0-9
) Close non capture group

Note that you don't need the /m flag as there are no anchors in the pattern.

Regex demo

const regex = /soyad[ıi](.+?)(?:S[ıi]n[ıi]f[ıi]|n(?:o|umara)|[0-9])/gi;
const str = "2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞASınıfıE10/ENo303\n";
console.log(Array.from(str.matchAll(regex), m => m[1]));

mplungjan · Accepted Answer · 2021-07-16 12:03:40Z

1

This might do it

const str = `2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞASınıfıE10/ENo303
2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞAnumaraE10/ENo303
2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞAnoE10/ENo303`
const re = /(?:Soyad(ı|i))(.*?)(?:S(ı|i)n(ı|i)f(ı|i)|no|numara)/gmi
console.log([...str.matchAll(re)].map(x => x[2]))

ES5

const str = `2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞASınıfıE10/ENo303
2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞAnumaraE10/ENo303
2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞAnoE10/ENo303`
const re = /(?:Soyad(ı|i))(.*?)(?:S(ı|i)n(ı|i)f(ı|i)|no|numara)/gmi
const res = []
let match;
while ((match = re.exec(str)) !== null) res.push(match[2])

console.log(res)

edited Jul 16, 2021 at 12:03

answered Jul 16, 2021 at 11:37

mplungjan

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4 Comments

Kaepxer Over a year ago

My bad, I didn't mentioned but I'm coding in React Native and matchAll() is not working on Android. It needs external library for this, so I'm not prefering this solution until I have no choice.

mplungjan Over a year ago

This is my text. I'm trying to find the word between "Soyadı" and "Sınıfı - this is the answer that will find the word. It is not a replace statement because that is not what you asked for. Replace statement will fail if the string changes

Kaepxer Over a year ago

IDK what do you mean by "replace statement will fail if the string changes" but when I try it with different strings It gave me the correct word.

Kaepxer Over a year ago

Soyadı means "surname" in Turkish. I'm trying to find surname. So, my bad again not to say that.

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