Sum values in Python

Question

I'm trying to get a list like this, where the two collected numbers are sum together and deliver the final result of that sum team1Goals + team2Goals:

FT      4 + 1 - Atletico El Vigia v Llaneros de Guanare
Postp.  1 + 2 - Deportivo Lara B v Atletico El Vigia
Postp.  0 + 0 - Llaneros de Guanare v Urena SC
FT      1 + 0 - Rayo Zuliano v Universidad de Los Andes FC

Expected Result:

FT      5 - Atletico El Vigia v Llaneros de Guanare
Postp.  3 - Deportivo Lara B v Atletico El Vigia
Postp.  0 - Llaneros de Guanare v Urena SC
FT      1 - Rayo Zuliano v Universidad de Los Andes FC

I tried using the sum() method, but it gives me an error and even giving me a hint that I honestly don't know how to go about using:

TypeError: sum() can't sum strings [use ''.join(seq) instead]

    response = requests.get(url, headers=headers).json()
    stages = response['Stages']
    for stage in stages:
        events = stage['Events']
        for event in events:
            outcome = event['Eps']
            team1Name = event['T1'][0]['Nm']
            if 'Tr1OR' in event.keys():
                team1Goals = event['Tr1OR']
            else:
                team1Goals = '0'
            
            team2Name = event['T2'][0]['Nm']
            if 'Tr2OR' in event.keys():
                team2Goals = event['Tr2OR']
            else:
                team2Goals = '0'
            print('%s\t%s - %s v %s' %(outcome, [sum(team1Goals,team2Goals)], team1Name, team2Name))

Elaborate your question on What you are getting? and What you want? — Abhishek Prajapat
– Abhishek Prajapat, Commented Jul 26, 2021 at 3:32

Ella Blackledge · Accepted Answer · 2021-07-26 04:11:23Z

1

Type cast the string variables to integers:

print('%s\t%s - %s v %s' % (outcome, sum([int(team1Goals),int(team2Goals)]), team1Name, team2Name))

edited Jul 26, 2021 at 4:11

answered Jul 26, 2021 at 3:53

Ella Blackledge

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1 Comment

Digital Farmer Over a year ago

Please edit your answear to complete model, like this: sum([int(team1Goals),int(team2Goals)]) or print('%s\t%s - %s v %s' % (outcome, sum([int(team1Goals),int(team2Goals)]), team1Name, team2Name)), thanks a lot for support! Perhaps older users may complain about your simple answer, I've seen it happen, so to lessen the chance of you losing points in the answer, I recommend doing this.

Kshitijthegreat · Accepted Answer · 2021-07-26 03:19:12Z

1

Sum can add up all values in a array given that they are of the same type. You can only use float and integers, while you have used strings.

answered Jul 26, 2021 at 3:19

Kshitijthegreat

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2 Comments

Digital Farmer Over a year ago

Hi mate, would you have any way to add the answer on how I could modify my code so that the result I'm looking for is achieved? Thanks in advance!

Kshitijthegreat Over a year ago

It seems that you need to add the numbers and not concatenate, so first convert them to integers using the int() function.

Hridaya Agrawal · Accepted Answer · 2021-07-26 03:24:00Z

1

So, The sum is only for integers, adding integers, That's what the error says, and has the solution too

Use: variable_name = str(team1Goals) + str(team2Goals)

edited Jul 26, 2021 at 3:24

answered Jul 26, 2021 at 3:18

Hridaya Agrawal

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2 Comments

Digital Farmer Over a year ago

Hi mate, I tried to use it like this, but the result was another error: TypeError: str.join() takes exactly one argument (2 given)

jpaodev Over a year ago

The .join() function is used, to connect a list or other iterable element using a provided string. if you want to use the .join() function, you'd have to use it like this: ", ".join(goals), while goals could be a list. Read here for more reference: w3schools.com/python/ref_string_join.asp

Digital Farmer · Accepted Answer · 2021-07-26 18:43:40Z

1

I am not sure if I got your question correctly, but (now) as I understand is that we can change the STR to INT by doing the following:

print('%s\t%s - %s v %s' % (outcome, sum([int(team1Goals),int(team2Goals)]), team1Name, team2Name))

edited Jul 26, 2021 at 18:43

Digital Farmer

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answered Jul 26, 2021 at 3:27

IHA87

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1 Comment

Digital Farmer Over a year ago

Hello mate, let's assume that I have team1Goals as 1 and team2Goals as 5, the result I expect is 6, but in your indication the achieved result is 5.

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