How to convert this curl command into java command

Question

i need to convert the following curl command into java command.

curl https://api.linkedin.com/v2/me -H "Authorization: Bearer xxx"

I writed this code:

public static void main(String[] args) throws MalformedURLException, IOException{

    HttpURLConnection con = (HttpURLConnection) new URL("https://api.linkedin.com/v2/me").openConnection();

    con.setRequestMethod("POST");
    con.setRequestProperty("Authorization", "Bearer xxx");
    con.setDoOutput(true);
    con.setDoInput(true);
    con.getOutputStream().write("LOGIN".getBytes("UTF-8"));
    con.getInputStream();
}

but I get an error:

Exception in thread "main" java.io.FileNotFoundException: https://api.linkedin.com/v2/me
    at java.base/sun.net.www.protocol.http.HttpURLConnection.getInputStream0(HttpURLConnection.java:1915)
    at java.base/sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1515)
    at java.base/sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(HttpsURLConnectionImpl.java:250)
    at testiamo.main(testiamo.java:18)

Try HttpsURLConnection con = (HttpsURLConnection)new URL("https://api.linkedin.com/v2/me").openConnection(); (import javax.net.ssl.HttpsURLConnection;) — g00se
– g00se, Commented Aug 3, 2021 at 10:51

Renis1235 · Accepted Answer · 2021-08-03 10:55:31Z

1

I would go with Apache HttpClient

And perform the call this way:

        CloseableHttpClient client = HttpClientBuilder.create().build();

        HttpPost postRequest = new HttpPost("https://api.linkedin.com/v2/me");
        postRequest.addHeader("Authorization", "Bearer xxx");

        // You could also send something through JSON...
        if(requestBody != null)
        {
            postRequest.addHeader("content-type", "application/json");
            StringEntity jsonEntity = new StringEntity(requestBody);
            postRequest.setEntity(jsonEntity);
        }

        // Getting the response
        HttpResponse rawResponse = client.execute(postRequest);
        final int status = rawResponse.getStatusLine().getStatusCode();
        final StringBuilder response = new StringBuilder();

        // If status == 200 then we get the response (which could be JSON, XML and so on) and save it as a string.
        if(status == HttpStatus.SC_OK)
        {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    rawResponse.getEntity().getContent()));

            String inputLine;

            while ((inputLine = reader.readLine()) != null)
            {
                response.append(inputLine);
            }

            reader.close();
            client.close();
        }
        else
        {
            client.close();
            throw new RuntimeException("Error while doing call!\nStatus: "+ status);
        }

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answered Aug 3, 2021 at 10:55

Renis1235

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3 Comments

xRobot Over a year ago

I get this error: ago 04, 2021 10:30:17 AM org.apache.http.client.protocol.ResponseProcessCookies processCookies WARNING: Invalid cookie header: "Set-Cookie: li_gc=MTswOzE2MjgwNjU4MTc7MjswMjFHaojFfu7ZrccbD2V9NU7pLUJlhg+my7cV7lmf3L/aRg==; Domain=.linkedin.com; Expires=Fri, 21 Jul 2023 00:02:44 GMT; Path=/; Secure; SameSite=None". Invalid 'expires' attribute: Fri, 21 Jul 2023 00:02:44 GMT Exception in thread "main" java.lang.RuntimeException: Error while doing call! Status: 401 at testiamo.main(testiamo.java:47) Process finished with exit code

Renis1235 Over a year ago

The question as has been asked above has been answered since the call is performed and you get as a response the HTTP STATUS 401. That error code means that you are unauthorized. If you need help regarding this error, I would suggest asking another specific question and put all the details in there. I will gladly help. httpstatuses.com/401

xRobot Over a year ago

Thanks, I have just asked another question: stackoverflow.com/questions/68648697/…

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