Use split function to split recursively in python

Question

I have written a piece of code which takes a keyword and splits a name using that specific keyword, however as split returns the list, now I want to individually check the elements of the returned list and again split it using a different keyword(if it exists), but this time I dont want another sublist to be returned, rather then the elements should get extended in the same list.

Code below :-

def get_comb_drugs(keyword, name):

    if keyword in name:
        name = name.split(keyword)

    return name

print(get_comb_drugs(", polymer with", "Acetaldehyde, polymer with ammonia and formaldehyde"))

The output I get is:

['Acetaldehyde', ' ammonia and formaldehyde']

however, I want to split 'ammonia and formaldehyde' again using " and " keyword and the exact output I want is:

['Acetaldehyde', ' ammonia', 'formaldehyde']

Guide me in achieving the desired result.

blhsing · Accepted Answer · 2021-08-04 07:57:42Z

1

You can use re.split instead with an alternation pattern:

import re
separators = [', polymer with', ' and ']
re.split('|'.join(separators), 'Acetaldehyde, polymer with ammonia and formaldehyde')

This returns:

['Acetaldehyde', ' ammonia', 'formaldehyde']

edited Aug 4, 2021 at 7:57

answered Aug 4, 2021 at 5:19

blhsing

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4 Comments

Rajsxx Over a year ago

Yep, but I cannot explicitly pass ', polymer with' and other pattern. I have lots of such keywords.

blhsing Over a year ago

You can join these separators into an alternation pattern with the '|'.join method, as shown in my edited answer.

Rajsxx Over a year ago

I get your point, but I need to pass many such keywords which I have in a single function which checks and returns the elements in a single list.

blhsing Over a year ago

@Rajsxx When I said you can use '|'.join to join the separators I meant the separators as a list, exactly what you say you need. I've edited my answer so that you can see the point more clearly.

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