Print x number of list and then insert new line in python

So I was toying around with the yesterday but I had to go to work before I could finished it up. The size variable lets you change the length and it prints it out nicely on the output. If you do need to add brackets to the output that should be easy enough.

Hopefully this points you in the right direction! 👍

myList = ["a", "b", "c", "d", "e", "f", "g", "h", "i"]
size = 5  # Number Per Row
startIndex = 0 # Start at the beginning index of myList

try:
    for x in range(len(myList)):
        for y in range(size):
            if startIndex >= len(myList):
                break
            print(myList[startIndex], end=" ")
            startIndex = startIndex + 1
        print()
        if startIndex >= len(myList):
            break
except IndexError:
    print("\nIndex Error")  # Left this in for debugging purposes

Try pprint.

import pprint
foo = [1, 2, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
pp = pprint.PrettyPrinter(width=30, compact=True)
pp.pprint(foo)

Results in:

[1, 2, 1, 2, 1, 1, 1, 1, 1, 1,
 1, 1, 1, 1, 1, 1, 1, 2, 2, 1,
 1, 1, 1, 1, 1, 1, 2, 1, 1, 1,
 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
 1, 1, 1, 1, 1, 1, 1]

You can play around with the width and indenting, etc...

If you don't want to use a library, here is one way to do it:

for i in range(len(l)//10+1):
    if i==0:
        k=str(l[i*10:i*10+10])
        k=k[:-1]+','
        print(k)
    elif i==len(l)//10:
        k=str(l[i*10:i*10+10])
        k=k[1:-1]+']'
        print(k)
    else:
        k=str(l[i*10:i*10+10])
        k=k[1:-1]+','
        print(k)

Output:

[1, 2, 1, 2, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 2, 2, 1,
1, 1, 1, 1, 1, 1, 2, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1]

Try this. I have rigorously tested this one.

n = [1, 2, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]

i = 0

j = len(n)

j = j - j%10

if len(n)%10==0:
    j -= 10

print(end='[')

while i<j:
    print(*n[i:i+10], sep=',', end=',\n')
    i += 10

print(*n[i:], sep=',', end=']') 

Output:

[1,2,1,2,1,1,1,1,1,1,
1,1,1,1,1,1,1,2,2,1,
1,1,1,1,1,1,2,1,1,1,
1,1,1,1,1,1,1,1,1,1,
1,1,1,1,1,1,1,1,1,1,
1,1,1,1,1,1,1,1,1,1,
1,1,1,1,1,1,1]

The example given has 67 elements. My output contains 7 lines. First 6 lines with 10 elements each & the last one with 7 elements. You can replace 10 by any number you want.

I would like to add another answer. It is more pythonic and one-line code.

a, x = list(range(10,77)), 5
print('[', *[str(i)+',' if (j+1)%x!=0 else str(i)+',\n' for j, i in enumerate(a[:-1])],sep='',end=str(a[-1])+']')

Output:

[10,11,12,13,14,
15,16,17,18,19,
20,21,22,23,24,
25,26,27,28,29,
30,31,32,33,34,
35,36,37,38,39,
40,41,42,43,44,
45,46,47,48,49,
50,51,52,53,54,
55,56,57,58,59,
60,61,62,63,64,
65,66,67,68,69,
70,71,72,73,74,
75,76]