TypeError when passing a bash variable into a python script

Question

When I run the bash program that calls the python script below I get this error: line 12, in roundup return int(int(math.ceil(x / 1000)) * (10**3)) TypeError: unsupported operand type(s) for /: 'str' and 'int' When the python script is run by itself there are no issues or errors. I checked to make sure that the bash variable was not a float and it is not on both programs. I am not sure how to fix this. I tried int(int(math.ceil(x / 1000)) * (10****3)) and int(math.ceil(x / 1000)) * (10**3)

import math
import os

pdiv=os.environ["div"]
print(pdiv)
#pdiv=931573 in both the bash srcipt that is calling this python script and the python script
divi=str(pdiv)
divide=len(divi)


if divide >= 4 and divide < 7:
    def roundup(x):
        return int(int(math.ceil(x / 1000)) * (10**3))
    z=roundup(pdiv)
    array = [int(x) for x in str(z)]
    if z == 4: 
       byte=str(array[0]) +'k'
        
        
    elif z == 5:
        byte=str(array[0]) + str(array[1]) + 'k'
        
    elif divide == 6:
        byte=str(array[0]) + str(array[1]) + str(array[2]) + 'k'
        

elif divide >= 7 and divide < 10:
    def roundup(x):
        return int(int(math.ceil(x / 1000000)) * (10**6))
    z=roundup(pdiv)
    array = [int(x) for x in str(z)]
    if divide == 7:
        byte=str(array[0]) +'m'
        
    elif divide == 8:
        #byte=print(array[0], end="");print(array[1], end="");print('m')
        byte=str(array[0]) + str(array[1]) + 'm'
        
    elif divide == 9:
        byte=str(array[0]) + str(array[1]) + str(array[2]) + 'm'
        
    
file = open("Bytes.txt", "w")
file.write(byte)
file.close

The values from os.environ[...] are always strings. Convert pdiv to int or float. — Yevhen Kuzmovych
– Yevhen Kuzmovych, Commented Aug 4, 2021 at 16:23
Don't define functions inside if blocks, define them globally. If you need different denominators and exponents, make them function parameters. — Barmar
– Barmar, Commented Aug 4, 2021 at 16:26

Hai Vu · Accepted Answer · 2021-08-04 20:37:41Z

1

The error is from the expression: x / 1000. In your script, x is a string, which you get from an environment variable. When you attempt to divide a string by an int, you get that error. To fix, you need to convert the string into a number:

def roundup(x):
    x = int(x)
    return int(int(math.ceil(x / 1000)) * (10**3))

answered Aug 4, 2021 at 20:37

Hai Vu

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