using for Loop to build a file name and save it

Question

for i in range(1,151):
 Path = './Result/Normal_%d'%i
 Normal_i.to_csv(Path, sep=',' , header=None , index=None)

I would like to use for loop to save a file that is name Normal_1, Normal_2 ...Normal_150 and I found out that using "Normal_i" in for loop makes an error. What Can I do to save a file that is named Normal_1, Normal_2 in for loop?

What error did you get?

Mahi
– Mahi

2021-08-05 08:28:14 +00:00
Commented Aug 5, 2021 at 8:28 — Mahi
– Mahi, Commented Aug 5, 2021 at 8:28

Seonghun · Accepted Answer · 2021-08-05 08:29:04Z

1

Path = './Result/Normal'
for i in range(1,151):
 Normal_i.to_csv(Path+str(i), sep=',' , header=None , index=None)

answered Aug 5, 2021 at 8:29

Seonghun

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Comments

A.M. Ducu · Accepted Answer · 2021-08-05 09:21:30Z

0

A good answer has already been given, but here is a fun python thing you could try:

eval(f"Normal_i.to_csv({Path}File{i}, sep=',' , header=None , index=None)")

About eval().

PS: I do not endorse doing this.

edited Aug 5, 2021 at 9:21

answered Aug 5, 2021 at 8:37

A.M. Ducu

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3 Comments

user15801675 Over a year ago

Why to use eval unnecessarily?

Mahi Over a year ago

eval is the opposite of pythonic. It's like using an excavator to hammer down a nail.

Matthias Over a year ago

You should read this: Eval really is dangerous

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