How to loop if there are multiple variables?

Question

For example

a = @(

"test1",

"test2"

)

b = @(

"test3",

"test4"

)

one is

foreach ($c in $a) {

ehco $c

}

What should I do if I have more than one?

iRon · Accepted Answer · 2021-08-11 09:00:52Z

1

Or create an (ordered) hashtable:

$hashtable = [Ordered]@{ a = @("test1", "test2"); b = @("test3", "test4") }
foreach ($Key in $HashTable.Keys) {
    foreach ($Item in $HashTable[$Key]) {
        echo $Item
    }
}

Yields:

test1
test2
test3
test4

answered Aug 11, 2021 at 9:00

iRon

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Comments

Mickey Cohen · Accepted Answer · 2021-08-11 07:16:50Z

0

You cannot do a foreach on more than one object. You can do a for loop, but it will break if the arrays are not of the same size Here's an example with a check on the arrays size:

if ($a.Count -eq $b.Count)
{
    for ($i=0; $i -lt $a.count; $i++)
    {
        $a[$i]
        $b[$i]
    }
}

answered Aug 11, 2021 at 7:16

Mickey Cohen

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1 Comment

Abraham Zinala Over a year ago

What if b is greater than a?

Gyula Kokas · Accepted Answer · 2021-08-11 07:19:15Z

0

You could do it like this:

$a = @(
"test1",
"test2"

)
$b = @(
"test3",
"test4"
)
foreach ($c in ($a,$b)) {
    echo $c
}

answered Aug 11, 2021 at 7:19

Gyula Kokas

1416 bronze badges

Comments

Venkataraman R · Accepted Answer · 2021-08-11 09:09:28Z

0

You can add the arrays and then loop through each item.

$a = @(

"test1",

"test2"

)

$b = @(

"test3",

"test4"

)

foreach($item in ($a + $b))
{
write-host $item
}

test1
test2
test3
test4

answered Aug 11, 2021 at 9:09

Venkataraman R

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Comments

Avshalom · Accepted Answer · 2021-08-11 12:49:28Z

0

$a = @("test1","test2"); $b = @("test3","test4")
$a,$b | % {$_}

test1
test2
test3
test4

answered Aug 11, 2021 at 12:49

Avshalom

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