Format string based on number array using '-' to separate adjacent numbers and ',' for non adjacent numbers

Question

Help me write a function that will have the following results...

[1,5,9] => "1,5,9"
[1,2,3,5] => "1-3,5"
[1,2,5,6] => "1-2,5-6"
[1,2,3,7,8,10] => "1-3,7-8,10"
the array will always be in ascending order.

here is the code from my use case but all my variations print incorrect results.

var testArray = [{
    book: "Genesis",
    chapter: "1",
    verse: "1"
  },
  {
    book: "Genesis",
    chapter: "1",
    verse: "2"
  },
  {
    book: "Genesis",
    chapter: "1",
    verse: "3"
  },
  {
    book: "Genesis",
    chapter: "1",
    verse: "5"
  },
  {
    book: "Genesis",
    chapter: "1",
    verse: "10"
  },
  {
    book: "Genesis",
    chapter: "1",
    verse: "9"
  },
  {
    book: "Genesis",
    chapter: "1",
    verse: "17"
  },
  {
    book: "Genesis",
    chapter: "1",
    verse: "16"
  },
  {
    book: "Genesis",
    chapter: "1",
    verse: "18"
  },
];

function formatHandler() {
  //put the array in ascending order by verse
  const current = this.testArray.sort((a, b) => {
    return parseFloat(a.verse) - parseFloat(b.verse);
  });
  const shrtBk = current[0].book.slice(0, 3);
  let fmtdText = "";
  let i = 0;
  for (i = 0; i < current.length; i++) {
    const zero =
      typeof current[i - 1] === "undefined" ?
      Number(current[i].verse) :
      Number(current[i - 1].verse);
    const first = Number(current[i].verse);
    const second =
      typeof current[i + 1] === "undefined" ?
      -1 :
      Number(current[i + 1].verse);
    const third =
      typeof current[i + 2] === "undefined" ?
      -1 :
      Number(current[i + 2].verse);
    if (i === 0) {
      fmtdText += `${shrtBk} ${current[0].chapter}:${current[0].verse}`;
    } else if (
      second - first === 1 &&
      third - second === 1 /*&& second === not null*/
    ) {
      i++;
    } else if (
      second - first === 1 &&
      third - second !== 1 &&
      first - zero !== 1
    ) {
      fmtdText += `,${first}`;
    } else if (
      second - first === 1 &&
      third - second !== 1 /*&& second === not null*/
    ) {
      fmtdText += `-${second}`;
      i++;
    } else if (second - first !== 1) {
      fmtdText += `,${first}`;
    }
    console.log(fmtdText);
  }
}
formatHandler()

georg · Accepted Answer · 2021-08-12 17:47:21Z

2

Ok, how about this

function formatWithRanges(ary) {
    let res = [],
        last = null

    for (let x of ary) {
        if (last && last[1] + 1 === x)
            last[1]++
        else
            res.push(last = [x, x])
    }

    return res
        .map(r => r[0] === r[1] ? r[0] : r[0] + '-' + r[1])
        .join(',')
}

console.log(formatWithRanges([1, 5, 9]))
console.log(formatWithRanges([1, 2, 3, 5]))
console.log(formatWithRanges([1, 2, 5, 6]))
console.log(formatWithRanges([1, 2, 3, 7, 8, 10]))

answered Aug 12, 2021 at 17:47

georg

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1 Comment

David Gordon Over a year ago

It seems to be working, I will implement it in a bit to see if I have any further questions!

AlexSp3 · Accepted Answer · 2021-08-12 18:13:46Z

0

Use .map() to modify the array and put a "-" or a "," depends on the following number. Then, take a substring to erase the last ",":

function range(a) {

  const s = a.map((e, i) => {
      if (e + 1 === a[i + 1]) {
         if (e - 1 !== a[i - 1]) 
           return e + "-";
      } else return e + ","; 
  }).join("");

  return s.substring(0, s.length - 1);
}

console.log(range([1, 5, 9]))
console.log(range([1, 2, 3, 5]))
console.log(range([1, 2, 5, 6]))
console.log(range([1, 2, 3, 7, 8, 10]))

edited Aug 12, 2021 at 18:13

answered Aug 12, 2021 at 18:02

AlexSp3

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