PHP not executing a shell exec command

Question

To keep this simple this code works:

<?php
$sinfo = shell_exec('ss -t -r state established');
echo "<pre>$sinfo</pre>";
?>

And this code code doesn't:

<?php
$sinfo = shell_exec('ss -H -t -r state established | awk '{$1=$2=""; print $0}'');
echo "<pre>$sinfo</pre>";
?>

Does anyone know how I can get the code that doesn't work to work?

I have ran the command in a normal terminal and they execute as expected, but when ran with PHP it cause a server 500 error - this seems to require a PHP code review from someone more competent than myself.

Thanks in advance :)

ss might not be available as a command in PHP's context; try /usr/sbin/ss ... — TheGentleman
– TheGentleman, Commented Aug 12, 2021 at 20:30
Yes KIKO thankyou thats the answer :) I needed to escape my single quotes- ill mark as complete — confused
– confused, Commented Aug 12, 2021 at 20:38

confused · Accepted Answer · 2021-08-12 20:46:33Z

1

Thanks to KIKO Software his link PHP quotes inside quotes. had the answer that I needed:

I had to escape the single quotes in the AWK

Working code:

<?php
$sinfo = shell_exec('ss -H -t -r state established | awk \'{$1=$2=""; print $0}\'');
echo "<pre>$sinfo</pre>";
?>

edited Aug 12, 2021 at 20:46

answered Aug 12, 2021 at 20:41

confused

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