How to declare an array of functions? [duplicate]

Question

Suppose I want to declare an array of functions, and try the following

int (*funcs)(int, int)[10];

But turns out that the following declaration stands for an function returning an array, which does not compile.

How can I declare an array of functions properly?

Or use std::function, std::vector<std::function<int(int, int)>> — prehistoricpenguin
– prehistoricpenguin, Commented Aug 17, 2021 at 8:49
try this: cplusplus.com/forum/beginner/4639 I've tried its working — Muhammed Aydogan
– Muhammed Aydogan, Commented Aug 17, 2021 at 8:50

Vlad from Moscow · Accepted Answer · 2021-08-17 08:44:58Z

4

Strictly speaking you may not declare an array of functions. You may declare an array of function pointers.

It seems you mean

int (*funcs[10])(int, int);

Another way is to introduce a using declaration (or a typedef declaration) like for example

using FP = int( * )( int, int );

FP funcs[10];

or

using FUNC = int ( int, int );

FUNC * funcs[10];

answered Aug 17, 2021 at 8:44

Vlad from Moscow

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2 Comments

The third option seems a little bit weird.

@KarenBaghdasaryan It has its own advantages because the same name FUNC you can using to declare a function and a function pointer..

songyuanyao · Accepted Answer · 2021-08-17 08:45:20Z

1

It should be

int (*funcs[10])(int, int);

Or ask help of using (or typedef).

using fp = int (*) (int, int);
fp funcs[10];

answered Aug 17, 2021 at 8:45

songyuanyao

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