I have a nested object as follows, and I want to find out the key name if value is given to me.
const a = {
"key1": 12,
"key2": {
"nkey1": 123,
"nkey2": 345
}
};
const temp = (obj, val) => {
return Object.keys(obj).find(key => !(typeof obj[key] === "object") ? obj[key] === val : temp(obj[key], val))
}
console.log(temp(a, 345));I wrote the above piece of code. But it gives me output as key2 whereas I want output as nkey2.
What am I doing wrong?
A function returns null if the value is not found, otherwise return the key.
const findKey = (obj, val) => {
if (typeof obj === "object") {
for (const key in obj) {
if (obj[key] === val) {
return key;
} else {
const result = findKey(obj[key], val);
if (result !== null) return result;
}
}
}
return null;
};
const a = {
key1: 12,
key2: {
nkey1: 123,
nkey2: 345,
nkey3: {
dkey1: 232,
dkey2: 777,
},
},
};
const output = findKey(a, 777);
console.log(output);You can use for-in loop, to iterate over keys. If the value of that key matches val, you can return the key. Else, you can check if value is an object, and use recursion, to check if val matches any value of key in that object.
const a = {
"key1": 12,
"key2": {
"nkey1": 123,
"nkey2": 345
}
};
const temp = (obj, val) => {
for (let i in obj) {
if(obj[i] === val){
return i;
} else if(typeof obj[i] === "object"){
return temp(obj[i], val);
}
}
}
console.log(temp(a, 345));Take a look at this:
const a = {
"key1": 12,
"key2": {
"nkey1": 123,
"nkey2": 345
}
};
// recursive loop
const find = (obj, search = null) => {
if (typeof obj === "object") {
for (const key in obj) { // loop over each property
if (obj.hasOwnProperty(key) && obj[key] === search) // if obj[key] is the value you are looking for (search)
return key; // return key
else {
let r = find(obj[key], search); // recursive call to find with the new object
if (r !== null) return r; // return key
}
}
}
return null; // default return value is null
}
console.log(12, find(a, 12));
console.log(123, find(a, 123));
console.log(345, find(a, 345));
console.log(0, find(a, 0));
return Object.keys.find()const a = { key1: { nkey1: 1, nkey2: 2, }, key2: { nkey3: 3, nkey4: 4, }, }; You can have a look of my answer.The find() function returns the first value of the the array for which the condition is true.
In the case of key === "key2" the recursive function is called which returns "nkey2" which results in the condition to be true and thats why "key2" is returned.
So again maybe to clear my way of thinking: You expect the find() function to return the result of a function call which is part of a condition. This wont work.
The condition is true on key2 so find returns key2.
Hope this helps you out!
typeof obj[key] === "object" ? obj[key] === val : temp(obj[key], val)- Ifobj[key]is an object, strictly-compare this object withvalotherwise calltemp(obj[key], val). You might want to re-think the order of operations... ;)