Check if array has element with specific length

Question

How to get element with specific length (ex: length = 7) in array If there's no element with length = 7, I want to print something. If I do inside the loop it will print many times base on number of element.

let txt = `abc klj 1123 MPM SN67990 MKP LJJ`
let arr = txt.split(' ')
console.log(arr)

for (let i = 0; i < arr.length; i++) {

    if (arr[i].length == 7) {
        console.log(arr[i])
    } 
    
    // TODO: if no element with length = 7 in arr
}

Duplicate of Check if all elements satisfy a condition with for-loop. — Sebastian Simon
– Sebastian Simon, Commented Aug 19, 2021 at 1:13
So add a variable and check outside var hasItem = false; for(...) { if(length 7) { hasItem=true;}} if(!hasItem) { alert('nope'); } — epascarello
– epascarello, Commented Aug 19, 2021 at 1:16

CertainPerformance · Accepted Answer · 2021-08-19 01:10:35Z

2

Check that .every one of the elements passes the length test.

if (arr.every(subarr => subarr.length !== 7)) {
  // then no array with length 7 exists
}

Another method - use a regular expression to match 7 characters, no array required.

if (!txt.match(/\b\S{7}\b/)) {
  // then no word exactly 7 characters long exists
}

answered Aug 19, 2021 at 1:10

CertainPerformance

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