Unable to parse XML attribute value into C# Enum in a desired way

Below shows one way to get the desired attribute values by using System.Xml.Serialization.

Create a class (name: HelperXml.cs) for the deserialize method.

HelperXml.cs

using System;
using System.Collections.Generic;
using System.Text;
using System.Xml;
using System.Xml.Serialization;

namespace XmlSerializationTest
{
    public class HelperXml
    {
        public static T DeserializeXMLFileToObject<T>(string xmlFilename)
        {
            //Usage: Class1 myClass1 = DeserializeXMLFileToObject<Class1>(xmlFilename);

            T rObject = default(T);
            if (String.IsNullOrEmpty(xmlFilename)) return default(T);

            using (System.IO.StreamReader sr = new System.IO.StreamReader(xmlFilename))
            {
                System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(typeof(T));

                //get data
                rObject = (T)serializer.Deserialize(sr);
            }

            return rObject;
        }
    }
}

Given the following XML:

<?xml version="1.0" encoding="UTF-8"?>
<DynamicFormExport Version="2">
  <DynamicForm>
    <DynamicField>
      <ListParameters>
        <Parameter ParentName="spGetPickListItems" ParameterName="DisplayCode" 
             Label="Display Code" Value="3" ValueTypeID="1" />
      </ListParameters>
    </DynamicField>
  </DynamicForm>
</DynamicFormExport>

Create classes for each of the following:

• DynamicFormExport
• DynamicForm
• DynamicField
• ListParameters
• Parameter

As far as naming strategy, in order to keep the classes in the desired order in VS, it can be helpful to do something like the following:

• DynamicFormExport (name: XmlDynamicFormExport)
• DynamicForm (name: XmlDynamicFormExportDynamicForm)
• DynamicField (name: XmlDynamicFormExportDynamicFormDynamicField)
• ListParameters (name: XmlDynamicFormExportDynamicFormDynamicFieldListParameters)
• Parameter (name: XmlDynamicFormExportDynamicFormDynamicFieldListParametersParameter)

Note: The class names I used is the class name above it pre-pended to the class name. (ex: XmlDynamicFormExport + DynamicForm = XmlDynamicFormExportDynamicForm). Although, the names in your XML are somewhat long, so a different naming strategy may be desirable.

XmlDynamicFormExport.cs

using System.Xml;
using System.Xml.Serialization;

namespace XmlSerializationTest
{
    [XmlRoot(ElementName = "DynamicFormExport", IsNullable = false)]
    public class XmlDynamicFormExport
    {
        [XmlAttribute(AttributeName = "Version")]
        public int Version { get; set; }

        [XmlElement(ElementName = "DynamicForm")]
        public XmlDynamicFormExportDynamicForm DynamicForm = new XmlDynamicFormExportDynamicForm();
    }
}

XmlDynamicFormExportDynamicForm.cs

using System.Xml;
using System.Xml.Serialization;

namespace XmlSerializationTest
{
    public class XmlDynamicFormExportDynamicForm
    {
        [XmlElement(ElementName = "DynamicField")]
        public XmlDynamicFormExportDynamicFormDynamicField DynamicField = new XmlDynamicFormExportDynamicFormDynamicField();
    }
}

XmlDynamicFormExportDynamicFormDynamicField.cs

using System.Xml;
using System.Xml.Serialization;

namespace XmlSerializationTest
{
    public class XmlDynamicFormExportDynamicFormDynamicField
    {
        [XmlElement(ElementName = "ListParameters")]
        public XmlDynamicFormExportDynamicFormDynamicFieldListParameters ListParameters = new XmlDynamicFormExportDynamicFormDynamicFieldListParameters();
    }
}

XmlDynamicFormExportDynamicFormDynamicFieldListParameters.cs

Note: Although it wasn't shown in the XML in the OP, it seems like more than 1 parameter could exist, so I used a List in the code below.

using System.Collections.Generic;
using System.Xml;
using System.Xml.Serialization;

namespace XmlSerializationTest
{
    public class XmlDynamicFormExportDynamicFormDynamicFieldListParameters
    {
        [XmlElement(ElementName = "Parameter")]
        public List<XmlDynamicFormExportDynamicFormDynamicFieldListParametersParameter> Parameter = new List<XmlDynamicFormExportDynamicFormDynamicFieldListParametersParameter>();
    }
}

Option 1:

XmlDynamicFormExportDynamicFormDynamicFieldListParametersParameter.cs

using System.Xml;
using System.Xml.Serialization;

namespace XmlSerializationTest
{
    public enum ParameterValueType
    {
        [XmlEnum(Name = "0")]
        Conditional,
        [XmlEnum(Name = "1")]
        Static
    }

    public class XmlDynamicFormExportDynamicFormDynamicFieldListParametersParameter
    {
        [XmlAttribute(AttributeName = "ParentName")]
        public string ParentName { get; set; }

        [XmlAttribute(AttributeName = "ParameterName")]
        public string ParameterName { get; set; }

        [XmlAttribute(AttributeName = "Label")]
        public string Label { get; set; }

        [XmlAttribute(AttributeName = "Value")]
        public int Value { get; set; }

        [XmlAttribute(AttributeName = "ValueTypeID")]
        public ParameterValueType ValueTypeID { get; set; }

    }
}

Usage (Option 1):

string filename = @"C:\Temp\DynamicFormExport.xml";
XmlDynamicFormExport dynamicFormExport = HelperXml.DeserializeXMLFileToObject<XmlDynamicFormExport>(filename);

foreach (var p in dynamicFormExport.DynamicForm.DynamicField.ListParameters.Parameter)
{
    System.Diagnostics.Debug.WriteLine("ParentName: " + p.ParameterName + " p.ValueTypeID: " + p.ValueTypeID.ToString());
}

Option 2:

XmlDynamicFormExportDynamicFormDynamicFieldListParametersParameter.cs

using System;
using System.Xml;
using System.Xml.Serialization;

namespace XmlSerializationTest
{
    [Serializable]
    public enum ParameterValueType : int
    {
        [XmlEnum(Name = "Conditional")]
        Conditional = 0,
        [XmlEnum(Name = "Static")]
        Static = 1
    }


    [Serializable()]
    public class XmlDynamicFormExportDynamicFormDynamicFieldListParametersParameter
    {
        [XmlAttribute(AttributeName = "ParentName")]
        public string ParentName { get; set; }

        [XmlAttribute(AttributeName = "ParameterName")]
        public string ParameterName { get; set; }

        [XmlAttribute(AttributeName = "Label")]
        public string Label { get; set; }

        [XmlAttribute(AttributeName = "Value")]
        public int Value { get; set; }

        [XmlAttribute(AttributeName = "ValueTypeID")]
        public int ValueTypeID { get; set; }

        //this property isn't written to XML, it's only for use in the app
        [XmlIgnore]
        public ParameterValueType ValueType
        {
            get { return (ParameterValueType)ValueTypeID; }

            set 
            {
                ValueTypeID = (int)value;
            }
        }
    }
}

Usage (Option 2):

string filename = @"C:\Temp\DynamicFormExport.xml";
XmlDynamicFormExport dynamicFormExport = HelperXml.DeserializeXMLFileToObject<XmlDynamicFormExport>(filename);

foreach (var p in dynamicFormExport.DynamicForm.DynamicField.ListParameters.Parameter)
{
    System.Diagnostics.Debug.WriteLine("ParentName: " + p.ParameterName + " p.ValueTypeID: " + p.ValueTypeID.ToString() + " p.ValueType: " + p.ValueType.ToString());
}