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I have a script that calls several other script and I run the script as sudo sudo ./main_script.sh

main_script.sh

#! /bin/bash
set -e

. /scritp1.sh
. /scritp2.sh
. /scritp3.sh
. /scritp4.sh

Is there any way to prevent one of the subscripts from running as sudo? (ie. scripts 1 2 and 4 run as sudo and script 3 run as normal)

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    Do the subscripts need to be run with . (or source), or can they be run in subprocesses, like normal scripts? Commented Aug 21, 2021 at 19:22
  • hi @GordonDavisson the subscripts are standalone scripts that are also sometimes run by themselves with .. Commented Aug 21, 2021 at 19:53

1 Answer 1

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This should achieve what you expected :

#! /bin/bash
set -e

. /scritp1.sh
. /scritp2.sh
sudo -u $SUDO_USER bash /scritp3.sh
. /scritp4.sh
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6 Comments

is that the right way round? So script3 will NOT run as sudo ?
script3 will run as the original user which is $SUDO_USER.
It's probably best to check whether $SUDO_USER is set first (in case the main script was run some other way, like when directly logged in as root). Something like if [ -z "$SUDO_USER" ]; then echo "Not running via sudo" >&2 ... Also, note that this will run scritp3.sh in a subprocess (as it must, to change users), not in the main shell process like . would.
@GordonDavisson Testing $SUDO_USER is set is a good point, which OP should do in the first place. As all scripts are standalone, OP should not use . or source.
@Philippe can you explain why I should not use . please.
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