Write files df in loop

Question

I have script that run over file for each "task" - unique id in my input table. After process, I want to write my output frame as file with name of task separately for each task. For example: task1.scv, task2.scv and so on.
my code that doesn't work:

for t in range(0,len(cv_tasks)):
      <...some process..>
df.to_csv('%s.csv' % cv_tasks[t])

jezrael · Accepted Answer · 2021-08-25 09:29:25Z

1

Here is possible simplify your task:

for i, t in enumerate(cv_tasks):
    print (i)
    print (t)
    <...some process..>
    #indentation necesary
    df.to_csv(f'{t}.csv')

edited Aug 25, 2021 at 9:29

answered Aug 25, 2021 at 8:17

jezrael

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2 Comments

TeoK Over a year ago

I also use value 't' as assign : n_rows = int(frame.loc[frame['task']==cv_tasks[t],['last_frame']].to_numpy())+1 , so in you code raise KeyError(key), I stil need save t as integer. When I change code to frame.loc[frame['task']==t, it;s no error but still make only one file

jezrael Over a year ago

@TeoK - Added i for integers. Answer was edited.

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