Count double in object and total for each JavaScript

Question

I need a bit help to get the double count and total price for each person. My object

const obj = [
  {'name':'sven','price':'10'},
  {'name':'jan','price':'12'},
  {'name':'john','price':'5'},
  {'name':'nick','price':'13'},
  {'name':'sven','price':'11'},
  {'name':'jan','price':'7'},
  {'name':'nick','price':'9'},
];

From this object I am counting double from key 'name'. e.g. sven 2, jan 1, john 1, nick 2. I use this code for that

const counts = [];
obj.map((x)=>{ 
  counts[x[0]] = (counts[x[0]] || 0) + 1;
});

Now I need also the total count of key 'price' saves together with each person and I can't seem to find a way to do so.

result should be an array of object e.g.

counts = [
  {'person':'sven','count':'2','totalPrice':'21'},
  {'person':'jan','count':'2','totalPrice':'19'}
]

I know how to get double and I know how to count total, but not in the same loop and save as 1 object. If someone could help me a bit pointing the right direction please.

Spectric · Accepted Answer · 2021-08-26 03:21:08Z

2

Here's an Array.reduce solution which checks whether the array contains an item with the same name property, and if so, increments its totalPrice property by the item's price property and its count property by 1.

const arr = [
  {'name':'sven','price':'10'},
  {'name':'jan','price':'12'},
  {'name':'john','price':'5'},
  {'name':'nick','price':'13'},
  {'name':'sven','price':'11'},
  {'name':'jan','price':'7'},
  {'name':'nick','price':'9'},
];

const result = arr.reduce((a, b) => {
  const found = a.find(e => e.name == b.name);
  if(found){
    found.totalPrice += +b.price;
    found.count++;
  }else{
    a.push({name:b.name, totalPrice: +b.price, count: 1})
  }
  return a
}, [])

console.log(result)

answered Aug 26, 2021 at 3:21

Spectric

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