I have class
class A:
def __init__(self):
print(i was used by :)
# if i call this class from the function below,
def my_func():
a = A()
# I need class A to print that "i was used in: my_func() "
Is there any solution for this ?
1 Answer
If you know the function name:
You could try something like:
class A:
def __init__(self, func):
print('i was used by:', func.__name__)
def my_func(func):
a = A(func)
my_func(my_func)
Output:
i was used by: my_func
This you would specify the function instance, which is the most optimal way here, then just use the __name__ to get the name of the function.
If you don't know the function name:
You could try the inspect module:
import inspect
class A:
def __init__(self):
print('i was used by:', inspect.currentframe().f_back.f_code.co_name)
def my_func():
a = A()
my_func()
Or try this:
import inspect
class A:
def __init__(self):
cur = inspect.currentframe()
a = inspect.getouterframes(cur, 2)[1][3]
print('i was used by:', a)
def my_func():
a = A()
my_func()
Both output:
i was used by: my_func
4 Comments
Jeesson Johney
Thanks but still, I have no idea which function is calling my class, I got a huge chunk of Django code in which i need to figure out from where an API request is fired. There is a class for handling that, but i have no idea from where it is used.
U13-Forward
@cod4 Edited my answer, check the Edit: part, that would work
Jeesson Johney
yea, that's exactly what i was looking for !
U13-Forward
@cod4 Your welcome, added an even shorter version, feel free to check it out :)
my_funcasprint("my_func willl now be calling A"). Or, just pass the function name to the constructor of A asA("my_func")and use it.