How to convert string in a datetime.datetime format into a datetime object?

Question

I have a raw log which print timestamp in format of datetime.datetime(2021, 9, 10, 10, 15, 0, 250362). I believe some conversion has failed in the underlying program (out of my control).

Since it's a string, I can't do it with strftime().

Any way I could translate this into a datetime?

"Since it's a string, i cant do it with strftime()"... Sitting next to strftime is its opposite function strptime. — blhsing
– blhsing, Commented Sep 10, 2021 at 5:58

Mark Tolonen · Accepted Answer · 2021-09-10 06:11:28Z

3

datetime.strptime() can be used to validate a string and parse a date/time:

from datetime import datetime

s = 'datetime.datetime(2021, 9, 10, 10, 15, 0, 250362)'
dt = datetime.strptime(s,'datetime.datetime(%Y, %m, %d, %H, %M, %S, %f)')
print(dt)

Output:

2021-09-10 10:15:00.250362

answered Sep 10, 2021 at 6:11

Mark Tolonen

181k26 gold badges182 silver badges278 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

U13-Forward · Accepted Answer · 2021-09-10 05:54:51Z

1

Try with this:

>>> s = 'datetime.datetime(2021, 9, 10, 10, 15, 0, 250362)'
>>> datetime.datetime(*map(int, s[s.find('(') + 1: -1].split(', ')))
datetime.datetime(2021, 9, 10, 10, 15, 0, 250362)
>>>

answered Sep 10, 2021 at 5:54

U13-Forward

71.8k15 gold badges100 silver badges125 bronze badges

Collectives™ on Stack Overflow

How to convert string in a datetime.datetime format into a datetime object?

2 Answers 2

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related