Sorting files from multiple directories in Python

Question

I am trying to read and store the file names from a directory to a list.

The folder structure is:

dataset
  ├── Type_a
  │   ├── a1_L.wav
  │   ├── a1_R.wav
  │   ├── a2_L.wav
  │   └── a2_R.wav
  └── Type_b
      ├── a1_L.wav
      ├── a1_R.wav
      ├── a2_L.wav
      └── a2_R.wav

The expected list output should be:

[[a1_L.wav,a1_R.wav],[a2_L.wav,a2_R.wav],[a1_L.wav,a2_R.wav],[a2_L.wav,a2_R.wav]]

Using the following code i am getting the file names but how it can be grouped into a list

import os
    for i, ret in enumerate(os.walk('./dataset/')):
        for i, filename in enumerate(ret[2]):
            print("filename is",filename)

The order of the filenames in a directory is hard is even possible to predict. What gives the order in your example? — Serge Ballesta
– Serge Ballesta, Commented Sep 16, 2021 at 12:48
Not quite sure what's the expected output.. a list of lists (of size 2) with the files that start with the same string? But you have a1_L.wav alongside a2_R.wav, which would break this rule. So what is the goal here? — MatBBastos
– MatBBastos, Commented Sep 16, 2021 at 13:22

score 1 · Accepted Answer · 2021-09-16 14:10:27Z

1

You could do it like this:-

import glob
import os

D={}

for r in glob.glob('./dataset/Type_*/*.wav'):
    t = r.split(os.path.sep)
    if not t[-2] in D:
        D[t[-2]] = []
    D[t[-2]].append(t[-1])
out = []
for v in D.values():
    v.sort()
    for i in range(0,len(v),2):
        out.append([v[i], v[i+1]])
print(out)

WARNING: This will fail if there are an odd number of files in any of the Type_* directories

edited Sep 16, 2021 at 14:10

answered Sep 16, 2021 at 13:14

user2668284

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2 Comments

Aniiya0978 Over a year ago

@DarkKnight This will fail for more entries

user2668284 Over a year ago

Thank you @Axe319 - I have corrected my answer

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