How i can convert array of object into array then a unique count of array

Question

const form = [
    {
        "_id": "61436aa8deef0390dcfdea79",
        "user": "613f92eb98da0c5facc1b4ca",
        "registerName": "Edwin",
        "email": "[email protected]",
        "category": "Urusan Lain Lain",
        "title": " Ah Yong",
        "contactNumber": "0191231232",
    --> "time": "8am",
        "dateBooking": "2021-09-18",
        "icNumber": "860909-49-5851",
        "date": "2021-09-16T16:02:48.457Z",
        "__v": 0
    },
    {
        "_id": "61436ab8deef0390dcfdea7a",
        "user": "613f92eb98da0c5facc1b4ca",
        "registerName": "ESTSETS",
        "email": "[email protected]",
        "category": "Daftar Baru",
        "title": " Ah Yong",
        "contactNumber": "0149530130",
    --> "time": "8am",
        "dateBooking": "2021-09-18",
        "icNumber": "123123123123",
        "date": "2021-09-16T16:03:04.211Z",
        "__v": 0
    },
    {
        "_id": "61436b1894116c90f82170b9",
        "user": "613f92eb98da0c5facc1b4ca",
        "registerName": "Ah Yong",
        "email": "[email protected]",
        "category": "Pertanyaan",
        "title": " Ah Yong",
        "contactNumber": "0149530130",
   -->  "time": "9am]",
        "dateBooking": "2021-09-18",
        "icNumber": "123654",
        "date": "2021-09-16T16:04:40.962Z",
        "__v": 0
    }
]

How can i convert time inside the object into

uniqueCount = [8am,9am,10am,8am,9am,10am,8am,9am,10am,11am];

and count the frequency of each time in the array? I want to have a result like:

8am = 3
9am = 3
10am = 3
11am = 1

I'm not sure whether this will work cause I would like to filter each time got how many people to create an condition.

Arvind Kumar Avinash · Accepted Answer · 2021-09-17 14:42:10Z

You can use Array#map to get an array of the time properties and then use Array#reduce to get an object with the frequencies.

const arr=[{_id:"61436aa8deef0390dcfdea79",user:"613f92eb98da0c5facc1b4ca",registerName:"Edwin",email:"[email protected]",category:"Urusan Lain Lain",title:" Ah Yong",contactNumber:"0191231232",time:"8am",dateBooking:"2021-09-18",icNumber:"860909-49-5851",date:"2021-09-16T16:02:48.457Z",__v:0},{_id:"61436ab8deef0390dcfdea7a",user:"613f92eb98da0c5facc1b4ca",registerName:"ESTSETS",email:"[email protected]",category:"Daftar Baru",title:" Ah Yong",contactNumber:"0149530130",time:"8am",dateBooking:"2021-09-18",icNumber:"123123123123",date:"2021-09-16T16:03:04.211Z",__v:0},{_id:"61436b1894116c90f82170b9",user:"613f92eb98da0c5facc1b4ca",registerName:"Ah Yong",email:"[email protected]",category:"Pertanyaan",title:" Ah Yong",contactNumber:"0149530130",time:"9am",dateBooking:"2021-09-18",icNumber:"123654",date:"2021-09-16T16:04:40.962Z",__v:0}];
const res = arr.map(x => x.time).reduce((acc, curr)=>{
  acc[curr] = (acc[curr] || 0) + 1;
  return acc;
}, {});
console.log(res);

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