Iterating over an array and appending its values to a dictionary in javascript

Question

I am trying to iterate over an dictionary that has values in form of array those values I want to put in a dictionary I am confused as to what should I do to obtain this

Here is the data that I want to iterate over :

{
t: ["20181019,20181022,...."],
o: ["180.34,189.45,..."],
h: ["180.99,181.40,..."],
l: ["178.57,177.56,...."],
c: ["179.85 ,178.75,...."]
}

Here is what the end product should look like :

[
    { time: '20181019', open: 180.34, high: 180.99, low: 178.57, close: 179.85 },
    { time: '20181022', open: 180.82, high: 181.40, low: 177.56, close: 178.75 },
    { time: '20190509', open: 193.31, high: 195.08, low: 191.59, close: 194.58 },
]

What have you tried? It is essential we hear your thoughts on it, so we can help you. If you do not think about the problem and obtain answers online, then you will not learn stuff. Add whatever no matter how little about your approach to the problem — Tushar Shahi
– Tushar Shahi, Commented Sep 21, 2021 at 13:43
Ok. You used .map()? Please add to the question. You will need to break the string too. Also will all the strings have equal numbers(/commas?. Add such details — Tushar Shahi
– Tushar Shahi, Commented Sep 21, 2021 at 13:48

DecPK · Accepted Answer · 2021-09-21 13:50:50Z

1

You can easily achieve the result using Object.keys, reduce

const obj = {
  t: ["20181019,20181022"],
  o: ["180.34,189.45"],
  h: ["180.99,181.40"],
  l: ["178.57,177.56"],
  c: ["179.85 ,178.75"],
};

const dict = { t: "time", o: "open", h: "high", l: "low", c: "close" };

const tempObj = Object.keys(obj).forEach((k) => (obj[k] = obj[k][0].split(",")));

const result = Array.from({ length: obj.t.length }, (_, i) => {
  return Object.entries(obj).reduce((acc, [k, v]) => {
        acc[dict[k]] = k === "t" ? v[i] : +v[i];
    return acc;
  }, {});
});

console.log(result);

/* This is not a part of answer. It is just to give the output fill height. So IGNORE IT */
.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Sep 21, 2021 at 13:50

DecPK

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4 Comments

user16834070 Over a year ago

its showing Uncaught TypeError: obj[k][0].split is not a function

user16834070 Over a year ago

as with all other answers

user16834070 Over a year ago

i am getting my data from this wesbite

Faruk Over a year ago

You misspelled the question. The data.t variable is an array but you typed a string ["20181019,20181022,...."]. it should have been like this ['20181019','20181022',...."]. Chek this stackblitz

Faruk · Accepted Answer · 2021-09-21 13:52:50Z

1

Here is the quick solution:

const data = {
  t: ['20181019,20181022,....'],
  o: ['180.34,189.45,...'],
  h: ['180.99,181.40,...'],
  l: ['178.57,177.56,....'],
  c: ['179.85 ,178.75,....'],
};

let prepared = {};
Object.keys(data).map((key) => {
  prepared[key] = data[key][0].split(',');
});

const res = prepared.t.map((tVal, index) => {
  return {
    time: tVal,
    open: prepared.o[index],
    high: prepared.h[index],
    low: prepared.l[index],
    close: prepared.c[index],
  };
});

console.log(res);

answered Sep 21, 2021 at 13:52

Faruk

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Comments

Ganesan C · Accepted Answer · 2021-09-21 14:03:04Z

0

Try below code.

var data = {
  t: ["20181019,20181022"],
  o: ["180.34,189.45"],
  h: ["180.99,181.40"],
  l: ["178.57,177.56"],
  c: ["179.85 ,178.75"]
}

var res = [];

const open = data.o.toString().split(",");
const high = data.h.toString().split(",");
const low = data.l.toString().split(",");
const close = data.c.toString().split(",");

data.t.toString().split(",").forEach((item, index) => {
  res.push({
    time : item,
    open : open[index],
    high: high[index],
    low: low[index],
    close: close[index]
  });
})

console.log(res);

answered Sep 21, 2021 at 14:03

Ganesan C

2771 gold badge3 silver badges9 bronze badges

1 Comment

user16834070 Over a year ago

Thank you for your answer

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