I don't know why this doesn't work. Any ideas?
let a = 0
if (a == 0) {return let a = value0}
else if (a == 1) {return let a = value1}
else {return let a = valuex}
console.log(a)The console always says 0. What should I do?
3 Answers
You shouldn't return from if branches, just assign a value to a:
let a = 0
if (a == 0) {a = value0}
else if (a == 1) {a = value1}
else {a = valuex}
console.log(a)
Comments
You are declaring a variable every time inside the condition. So variables will be scoped into brackets not outside of that brackets. So the global variable will not change in your case. And remove return. Solution is
let a = 0
if (a == 0) {
a = value;
}
else if (a == 1) {
a = value1;
}
else {
a = value;
}
console.log(a)
Comments
The problem here is the scope of 'a'.
let allows us to declare variables that are limited to the scope of a block statement,and once the block closes, it's scope ends.
let a = 0
//You don't need to redeclare a by using let
//Also you don't need to return anything since it's not a function
if (a == 0) { a = value0}
else if (a == 1) { a = value1}
else { a = valuex}
console.log(a)
letisn’t an expression. Why do you even havereturnthere? What are you actually testing? Onlyif(a == 0)will ever be true.