I am trying to convert a 1D array (81 characters + null) and put it into a 9 by 9 grid of characters.
void convertArray(char lineHolder[])
{
lineHolder[]; //I want this data
converted2d[9][9]; //to go into that data
}
int drag(){
char lineHolder[82];
int puzzle = SOLVABLE;
int last, i;
last = i = 0;
while ((last = getchar()) != EOF)
{
putchar(last);
lineHolder[i] = last;
i++;
}
return 0;
}
You can simply use memcpy().
char name[82] = ... ;
char puzzle[9][9];
memcpy(puzzle, name, sizeof puzzle);
The layout of both types is perfectly defined by the standard.
Alternatively, you can do it without copying by risking triggering Undefined behavior. Just cast name to char(*)[9] (a pointer to the row of 9 chars). Using this pointer will violate strict aliasing rule thus the outcome is not defined by C standard. However, it will likely work:
char (*puzzle)[9] = (char(*)[9])name;
// use puzzle[y][x] syntax later on
Use union:
union myunion
{
char name[81];
char puzzle[9][9];
};
or pointer to array.
char name[81];
char (*puzzle)[9] = name;
